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Naily [24]
3 years ago
11

Bill has $2.00 in quarters and dimes. the number of quarters is 4 less than twice the number of dimes. find the number of coins

of each type
Mathematics
1 answer:
Dafna1 [17]3 years ago
7 0
Define your variables:
Q: number of quarters
D: number of dimes

Next, create your equations
Q = 2D-4
25Q+10D=200

Because one variable (Q) is already written in terms of the other variable, D, you can already start solving with substitution.
25(2D-4)+10D=200
50D-100+10D=200
60D=300
D=5

Substitute D back into the other equation to find Q. 
Q=2D-4
Q=2(5)-4
Q=6

Substitute D and Q into the second equation to check.
25Q+10D=200
25(6)+10(5)=200
150+50=200

This works, so the answer is right! Bill has 6 quarters and 5 dimes.
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Answer:

i don't what you want me to do here...

You gave me the same problem just two different numbers so maybe the answer is 7... idek tho bro

k times x = 7

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Step-by-step explanation:

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mamaluj [8]

Answer:

Mean = 35

Variance = 291.7

Step-by-step explanation:

Data provided in the question:

X : 1, 2, 3, 4, 5, 6

All the data are independent

Thus,

The mean for this case will be given as:

Mean, E[X] = \frac{\textup{Sum of all the observations}}{\textup{Total number of observations}}

or

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or

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For 10 days, Mean = 3.5 × 10 = 35

And,

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Now, for this case of independent value,

E[X²] = \frac{1^2+2^2+3^2+4^2+5^2+6^2}{\textup{6}}

or

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or

E[X²] = \frac{91}{\textup{6}}

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Therefore,

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or

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or

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Answer:

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