Hi there!
Let th' two number be ' a ' and ' b ' [ a > b ]
According to th' question :-
→ The largest of two numbers is 12 more than the smaller number.
a = 12 + b ---(i)
→ Sum of the two numbers is 74.
a + b = 74
b = 74 - a ---(ii)
Substitute th' value of ' b in Eqn. :-
a = 12 + (74 - a)
a = 86 - a
a + a = 86
2a = 86
a =

= 43
Now,
Substitute th' value of ' a ' in Eqn. (ii)
b = 74 - b
b = 74 - 43
b = 31
Hence,
The required answer is :-
• The smaller number is 31
• The largest number is 43
~ Hope it helps!
Answer:
X = 12
4x + 12 = 5x
subtract 4x on each side and you're left with x=12
Seven hundred and thirteen thousand, two hundred and ninety eight
So what you do is go 5(3y+5)-4y=14 which equals 15y+25-4y=14 which turns into 11y+25=14 than you move the 25 over which equals 11y=-11 so y=-1 then you enter -1 in for y which looks like 5x-4(-1)=14 than you solve that which is 5x+4=14 than you move the 4 over and you get 5x=10 than x=2
x=2
y=-1
Answers: 
1. Switch sides

2. Subtract by 8 from both sides of equation.

3. Simplify.

4. Multiply by -1 from both sides of equation. (it's should be the reverse inequality).

5. Simplify.

6. Then you had to divide by 9 from both sides of equation.

7. Simplify.

8. Divide by the numbers.



9. Divide by the numbers.



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