All categories

4 years ago

I need help with adding and subtracting fractions

2 answers:

7 0

Answer is 3/72

multiply the denominator and numerator of 3/8 by 9 (27/72)
multiply the denominator and numerator of 3/9 by 8 (24/72)

this is to get the same denominator of 72

then just subtract
27/72 - 24/72 = 3/72

balu736 [363]4 years ago

4 0

Answer:
The result is 1/24

Explanation:
First step is to get the common denominator:
The common denominator here will be 8*9 = 72
Therefore:
3/8 = 27/72
3/9 = 24/72

Second step is to do the subtraction:
27/72 - 24/72 = (27-24) / 72 = 3/72

The last step is to simplify the result:
3/72 = 1/24

Hope this helps :)

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elena-s [515]

Answer:

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Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)

viktelen [127]

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}$

The first line segment can be parameterized by $\mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle$ with $0\le t\le1$ . Denote this first segment by $C_1$ . Then

$\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt$
$=108$

The second line segment ( $C_2$ ) can be described by $\mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle$ , again with $0\le t\le1$ . Then

$\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt$
$=-\dfrac{229}3$

Finally,

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3$

5 0

3 years ago

What is the midpoint of (-2,3) and (10,3) *simple answer please

Allushta [10]

The "midpoint formula" is the same as the "average formula:"

x-coordinate of the midpoint = average of -2 and 10:

= (-2 + 10) / 2 = 4

y-coordinate of the midpoint = average of 3 and 3:

= (3+3) / 2 = 3

Thus, the midpoint of the given line segment is (4,3).

5 0

3 years ago

When you multiply any whole number by the one before it, the result is always an even number.

polet [3.4K]

Verrrrrrry interesting ! / / / Every multiple of an even number is another even number. When you take any whole number and the one 'before' it ... no matter which direction 'before' means .... one of the numbers is even. So their product is a multiple of an even number, and it must be another even number.

8 0

3 years ago

F(x)=2x+5 find f(-6)

ser-zykov [4K]

Answer:

Step-by-step explanation:

f(x) = 2x + 5

f(-6)= 2(-6) + 5 = -12 + 5 = -7

4 0

3 years ago