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Maksim231197 [3]
3 years ago
8

I don’t get this question at all and I really need help on this.!

Mathematics
1 answer:
galina1969 [7]3 years ago
7 0

Answer:

C

Step-by-step explanation:

Vasily is incorrect. She left out the -10g

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I need help. How do i solve this?
Sphinxa [80]

Answer:

C

Step-by-step explanation:

Cool

7 0
3 years ago
The height of the javelin above the ground is symmetric about the line t = seconds. The javelin is 20 feet above the ground for
Levart [38]
I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
 PLEASE SEE ATTACHED IMAGE.

 Part 1:

 we must see in the graph the axis of symmetry of the given parabola.
 The axis of symmetry is the following vertical line:
 t = 2

 Answer:
 
The height of the javelin above the ground is symmetric about the line t = 2 seconds:

 Part 2:

 we must see the time t for which the javelin reaches a height of 20 feet for the first time.
 We have that when evaluating t = 1, the function is:
 h (1) = 20.

 To do this, just look at the graph.
 Then, we must observe the moment when it returns to be 20 feet above the ground.
 For this, we have from the graph that:
 h (3) = 20 feet

 Therefore, a height of 20 feet is again reached in 3 seconds.
 Answer:
 
The javelin is 20 feet above the ground for the first time at t = 1 second and again at t = 3 seconds

6 0
4 years ago
Which table contains the vertex of the graph represented by y=x^2-6x+4?
notka56 [123]

Answer:

Table B

Vertex is (3,-5)

Step-by-step explanation:

We are given with an equation of a parabola y=x^2-6x+4

Let is convert it into standard form of a parabola

y=x^2-6x+4

adding and subtracting 9 in the right hand side of the =

y=x^2-6x+9-9+4

y=x^2-2\times 3\times x+ 3^2-9+4

the first three terms of the right hand side forms the expression of square of difference

a^2-2 \times a \times b+b^2 = (a-b)^2

Hence

y=(x-3)^2-5

adding 5 on both sides we get

(y+5)=(x-3)^2

Comparing it with the standard equation of a parabola

X^2=4\times \frac{1}{4} \times Y

where X=x-3 and Y=y+5

The vertex of X^2=4\times \frac{1}{4} \times Y will be (0,0)

and thus vertex of

(y+5)=(x-3)^2 will be (3,-5)

Hence the Table B is our right answer

5 0
3 years ago
HELP PLEASE!!!!!!!
hodyreva [135]
They sold 50 salads in all.
5 0
3 years ago
Read 2 more answers
On March 8, 2017, one U.S dollar was worth 66.79 Indian rupees. On that date how many rupees was 63.64 dollars worth? Round your
Anit [1.1K]

Answer: ‭4,250.52 Rupees

Step-by-step explanation:

If one U.S. dollar was worth 66.79 Indian Rupees, it means that were you to exchange both currencies, a dollar would get you 66.79 Rupees and 66.79 Rupees would get you a Dollar.

If you had $63.64 Dollars therefore, the number of Rupees you could get is the amount of dollars multiplied by the amount of Rupees:

= 63.64 * 66.79

= ‭4,250.52 Rupees

5 0
3 years ago
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