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Ann [662]
4 years ago
8

What is the 25th term of the arithmetic sequence where a1=8 and a9=48 ? answers to choose from. a)113. b)118. c)123. d)128

Mathematics
2 answers:
Nookie1986 [14]4 years ago
7 0

Answer:

128

Step-by-step explanation:

Stella [2.4K]4 years ago
6 0
First we need to find "d" which is difference between any 2 successive members of the sequence. Because the sequence is arithmetic that means that the difference between any 2 successive members is same and constant.

This is the formula for any member of sequence at position "n"
An = A1 + (n-1)*d
d = (a9 - a1)/(9-1)
d = 5

Now we calculate 25th member:
a25 = a1 + (25-1)*5
a25 = 128

Answer is d)
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_____

<em>Additional comment</em>

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