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ehidna [41]
4 years ago
6

The height of the javelin above the ground is symmetric about the line t = seconds. The javelin is 20 feet above the ground for

the first time at t = seconds and again at t = seconds

Mathematics
1 answer:
Levart [38]4 years ago
6 0
I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
 PLEASE SEE ATTACHED IMAGE.

 Part 1:

 we must see in the graph the axis of symmetry of the given parabola.
 The axis of symmetry is the following vertical line:
 t = 2

 Answer:
 
The height of the javelin above the ground is symmetric about the line t = 2 seconds:

 Part 2:

 we must see the time t for which the javelin reaches a height of 20 feet for the first time.
 We have that when evaluating t = 1, the function is:
 h (1) = 20.

 To do this, just look at the graph.
 Then, we must observe the moment when it returns to be 20 feet above the ground.
 For this, we have from the graph that:
 h (3) = 20 feet

 Therefore, a height of 20 feet is again reached in 3 seconds.
 Answer:
 
The javelin is 20 feet above the ground for the first time at t = 1 second and again at t = 3 seconds

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