The height of the javelin above the ground is symmetric about the line t = seconds. The javelin is 20 feet above the ground for
the first time at t = seconds and again at t = seconds
1 answer:
I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
PLEASE SEE ATTACHED IMAGE.
Part 1:
we must see in the graph the axis of symmetry of the given parabola.
The axis of symmetry is the following vertical line:
Answer:
The height of the javelin above the ground is symmetric about the line t = 2 seconds:
Part 2:
we must see the time t for which the javelin reaches a height of 20 feet for the first time.
We have that when evaluating t = 1, the function is:
To do this, just look at the graph.
Then, we must observe the moment when it returns to be 20 feet above the ground.
For this, we have from the graph that:
Therefore, a height of 20 feet is again reached in 3 seconds.
Answer:
The javelin is 20 feet above the ground for the first time at t = 1 second and again at t = 3 seconds
PLEASE SEE ATTACHED IMAGE.
Part 1:
we must see in the graph the axis of symmetry of the given parabola.
The axis of symmetry is the following vertical line:
Answer:
The height of the javelin above the ground is symmetric about the line t = 2 seconds:
Part 2:
we must see the time t for which the javelin reaches a height of 20 feet for the first time.
We have that when evaluating t = 1, the function is:
To do this, just look at the graph.
Then, we must observe the moment when it returns to be 20 feet above the ground.
For this, we have from the graph that:
Therefore, a height of 20 feet is again reached in 3 seconds.
Answer:
The javelin is 20 feet above the ground for the first time at t = 1 second and again at t = 3 seconds
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(a) Animals by popularity; Dogs, Cats, Others, Horses.
(b) If 250 students were interviewed, 20 students have other pets.
(c) No, it was incorrect.
Step-by-step explanation:
Step 1; We arrange the different pets in chronological order, from the highest percent to the lowest percent;
1. Dogs - 67%,
2. Cats - 20%
3. Others - 8%,
4. Horses - 1%.
None is not included in this list.
Step 2; If 250 students were interviewed, 8% of those have other pets. So we need to calculate how much 8% of 250 is.
8% of 250 = × 250 = 0.08 × 250 = 20.
So 20 students had other pets.
Step 3; 20% of the interviewed students had cats. If 75 students had cats, we need to equate 20% to the 75 and find out how many students were actually interviewed.
20% × x = 75, 0.2 × x = 75,
x = = 375.
So if 375 students were interviewed, 75 students would have cats. So the estimate of 250 students being interviewed is incorrect.