$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
X&({{ a}}\quad ,&{{ b}})\quad 
% (c,d)
Y&({{ -8}}\quad ,&{{ 6}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)$

$\bf \left( \cfrac{-8+a}{2}~,~\cfrac{6+b}{2} \right)=\stackrel{M}{(-3,-1)}\implies 
\begin{cases}
\cfrac{-8+a}{2}=-3\\\\
-8+a=-6\\
\boxed{a=2}\\
----------\\
\cfrac{6+b}{2}=-1\\\\
6+b=-2\\
\boxed{b=-8}
\end{cases}$

5 0

3 years ago

The measures of the angles of a triangle are ∠A = (2x)°, ∠B = (x+14)°, ∠C = (x−38)° Determine the value of x. Determine A B and

nexus9112 [7]

Answer:

Step-by-step explanation:

Measures of angles are,

m∠A = (2x)°

m∠B = (x + 14)°

m∠C = (x - 38)°

By triangle sum theorem,

m∠A + m∠B + m∠C = 180°

2x + (x + 14) + (x - 38) = 180

(2x + x + x) + (14 - 38) = 180

4x - 24 = 180

4x = 204

x = 51

m∠A = 2(51)° = 102°

m∠B = (51 + 14)° = 65°

m∠C = (51 - 38)° = 13°

4 0

3 years ago