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3 years ago

How to find the rate in exponential growth formula A=P(1-r)^t

Mathematics

1 answer:

erma4kov [3.2K]3 years ago

8 0

R = rate
A = P(1-r)^t
A^t = P(1-r)
A^t/P = 1-r
(A^t/P)-1 = -r
r = -((A^t/P)-1)

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Gina is 136 cm tall and Rita is 1.32 m tall. Who is taller? How much taller?

marusya05 [52]

Gina is taller. The difference between both of their heights is 4 cm.

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4 years ago

In a one-way ANOVA, the __________ is calculated by taking the squared difference between each person and their specific groups

guapka [62]

Answer:

In a one-way ANOVA, the $SS_{within}$ is calculated by taking the squared difference between each person and their specific groups mean, while the $SS_{between}$ is calculated by taking the squared difference between each group and the grand mean.

Step-by-step explanation:

The one-way analysis of variance (ANOVA) is used "to determine whether there are any statistically significant differences between the means of two or more independent groups".

The sum of squares is the sum of the square of variation, where variation is defined as the spread between each individual value and the mean.

If we assume that we have p groups and each gtoup have a size $n_j$ then we have different sources of variation, the formulas related to the sum of squares are:

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A measure of total variation.

$SS_{between}=\sum_{j=1}^{p} n_j (\bar x_{j}-\bar x)^2$

A measure of variation between each group and the grand mean.

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8 0

3 years ago

Choose the solution(s) of the following system of equations x2 + y2 = 6 x2 – y = 6

ElenaW [278]

<h2>Answer</h2>

$x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1$

Or as ordered pairs: $(\sqrt{6} ,0),(-\sqrt{6} ,0),(\sqrt{5} ,-1),(-\sqrt{5} ,-1)$

<h2>Explanation</h2>

Lets solve our system of equations step by step

$x^2+y^2=6$ equation (1)

$x^2-y=6$ equation (2)

1. Solve for $x^2$ in equation (2)

$x^2-y=6$

$x^2=6+y$ equation (3)

2. Replace equation (3) in equation (1) and solve for $y$

$x^2+y^2=6$

$6+y+y^2=6$

$y^2+y=0$

$y(y+1)=0$

$y=0$ or $y=-1$

3. Replace the values of $y$ in equation (3) and solve for $x$

- For $y=0$

$x^2=6+y$

$x^2=6$

$x=\sqrt{6}$ or $x=-\sqrt{6}$

- For $y=-1$

$x^2=6+y$

$x^2=6-1$

$x^2=5$

$x=\sqrt{5}$ or $x=-\sqrt{5}$

So, the solutions of our system of equation are:

$x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1$

6 0

3 years ago

Read 2 more answers

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iragen [17]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

I️ need help with the your turn part

Helen [10]

Because the angle is a straight angle, it means that the total of DEC and CEF would be 180º. (CEF + DEF = 180º) With this information we can make the equasion:

(11x - 12) + (2x + 10) = 180

first, to find x:

to simplify (11x - 12) + (2x + 10) = 180, you add the two equations:

13x - 2 = 180

13x = 182

x = 182/13

x = 14

Now, insert the x (which we found that is 14) to each equation.

DEC: (11 x 14 - 12)

= 154 - 12 = 142

m DEC is 142º.

CEF: (2 x 14 + 10)

=28 + 10 = 38

m CEF is 38º.

<em>check: (CEF + DEC = 180º)</em>

therefore, the answers are correct :D

7 0

3 years ago