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Mumz [18]
3 years ago
11

11. A line passes through the point(0,1) and has slope 2. What is the equation of the line in slope-intercept form?​

Mathematics
2 answers:
cupoosta [38]3 years ago
4 0

Answer:

Y=2x+1

Step-by-step explanation:

pishuonlain [190]3 years ago
3 0
The equation is y=2x+1

the 2 you’re given is already slope so it will be m

y=mx+b of y=2x+b

b is the y-intercept and (0,1) is a point on the y-axis so its the y intercept

y=2x+1
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If cos28 = x/4, find x(3sf)
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Cos28 = x/4 so to get rid of the fraction , multiply each side by 4 so it'll be
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3 0
4 years ago
Please hurry!!!! 20 pts
Ivahew [28]

The slope for is JK 1/3 , the slope of LK is -2 , the slope of ML is 2/5 , and the slope of MJ is 3/2 . Quadrilateral JKLM is not a parallelogram because neither pair of opposite sides is parallel

Further explanation:

Given vertices are:

J(−4, 1) , K(2, 3) , L(5, -3) , and M(0, −5) .

We have to find the slopes before concluding any result

The formula for slope is:

m=\frac{y_2-y_1}{x_2-x_1}

So:

<u>Slope of JK:</u>

m_1=\frac{3-1}{2-(-4)}\\=\frac{2}{2+4}\\=\frac{2}{6}\\=\frac{1}{3}

<u>Slope of LK:</u>

m_2=\frac{-3-3}{5-2}\\=\frac{-6}{3}\\=-2

<u>Slope of ML:</u>

m_3=\frac{-3-(-5)}{5-0}\\=\frac{-3+5}{5}\\=\frac{2}{5}

<u>Slope of MJ:</u>

m_4=\frac{1-(-5)}{-4-0}\\=\frac{1+5}{-4}\\=\frac{6}{-4}\\=-\frac{3}{2}

As the slopes of all sides are different, the given quadrilateral is not a parallelogram because in order for the quadrilateral to be a parallelogram the opposite sides have to be parallel i.e. have equal slopes and there are no sides with equal slopes.

Keywords: Parallelogram, Quadrilateral

Learn more about quadrilateral at;

  • brainly.com/question/5191807
  • brainly.com/question/5312408

#LearnwithBrainly

6 0
3 years ago
A trough has ends shaped like isosceles triangles, with width 5 m and height 7 m, and the trough is 12 m long. Water is being pu
Svet_ta [14]

Answer:

\dfrac{dh}{dt}=21 \text{m/min}

the rate of change of height when the water is 1 meter deep is 21 m/min

Step-by-step explanation:

First we need to find the volume of the trough given its dimensions and shape: (it has a prism shape so we can directly use that formula OR we can multiply the area of its triangular face with the length of the trough)

V = \dfrac{1}{2}(bh)\times L

here L is a constant since that won't change as the water is being filled in the trough, however 'b' and 'h' will be changing. The equation has two independent variables and we need to convert this equation so it is only dependent on 'h' (the height of the water).

As its an isosceles triangle we can find a relationship between b and h. the ratio between the b and h will be always be the same:

\dfrac{b}{h} = \dfrac{5}{7}

b=\dfrac{5}{7}h this can be substituted back in the volume equation

V = \dfrac{5}{14}h^2L

the rate of the water flowing in is:

\dfrac{dV}{dt} = 6

The question is asking for the rate of change of height (m/min) hence that can be denoted as: \frac{dh}{dt}

Using the chainrule:

\dfrac{dh}{dt}=\dfrac{dh}{dV}\times \dfrac{dV}{dt}

the only thing missing in this equation is dh/dV which can be easily obtained by differentiating the volume equation with respect to h

V = \dfrac{5}{14}h^2L

\dfrac{dV}{dh} = \dfrac{5}{7}hL

reciprocating

\dfrac{dh}{dV} = \dfrac{7}{5hL}

plugging everything in the chain rule equation:

\dfrac{dh}{dt}=\dfrac{dh}{dV}\times \dfrac{dV}{dt}

\dfrac{dh}{dt}=\dfrac{7}{5hL}\times 6

\dfrac{dh}{dt}=\dfrac{42}{5hL}

L = 12, and h = 1 (when the water is 1m deep)

\dfrac{dh}{dt}=\dfrac{42}{5(1)(12)}

\dfrac{dh}{dt}=21 \text{m/min}

the rate of change of height when the water is 1 meter deep is 21 m/min

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4 years ago
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Answer:

inverse relationship

Step-by-step explanation:

This is inverse becuase as masss increases acceleration decreaes

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Answer:

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Step-by-step explanation:

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3 years ago
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