48
+14
-------
62
If you need more work:
Ones place: 8+4=12
Tens place: 40+10=50
Add up: 50+12=62
<span>lengths are in ratio 1:3
areas are in ratio
1 : 3</span>²<span> = 1: 9
area of ADG = 9 x 42 = 378 </span>
Answer:
60 inches long are the sides of the pillars.
Step-by-step explanation:
Given : A small bridge sits atop four cube shaped pillars that all have the same volume. the combined volume of the four pillars is 500 ft cubed.
To find : How many inches long are the sides of the pillars?
Solution :
Refer the attached picture below for Clarence of question.
The volume of the cube is 
Where, a is the side.
The combined volume of the four pillars is 500 ft cubed.
The volume of each cube is given by,

Substitute in the formula to get the side,

![a=\sqrt[3]{125}](https://tex.z-dn.net/?f=a%3D%5Csqrt%5B3%5D%7B125%7D)

We know, 1 feet = 12 inches
So, 5 feet =
inches
Therefore, 60 inches long are the sides of the pillars.
Answer:
7/20
Explanation:
In order to do this, you must first simplify all the equations to the simplest forms. Do this by simplifying 3/6 to 1/2. We know this because 3 is half of 6, therefore it would reduce down to 1/2. 7/10 is already simplified; we know this because 7 is a prime number and can’t do down any further
Now, multiply the two fractions buy multiplying the numerators and denominations together. In other words, 1 x 7 is 7 so your numerator is 7, and 2 x 10 is 20 so your denominator is 20.