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3 years ago

3^2 • 3^-8 • 3^0 i need help with this asap

Mathematics

2 answers:

pantera1 [17]3 years ago

6 0

Steps to solve:

3^2 • 3^-8 • 3^0

~Apple exponent rule [ a^b * a^c = a^b+c ]

3^2-8+0

~Simplify

3^-6

~Use exponent rule [ a^-b = 1/a^b ]

1/3^6

~Simplify

1/729

Best of Luck!

andrew-mc [135]3 years ago

6 0

Answer:

3^-6 which equals 1/3^6

Step-by-step explanation:

all you do is add the exponents.

3^0 is equal to 0 so that one doesn't matter, you just cross it out.

now you're left with 3^2x3^-8

so add 2+(-8) which is -6 so the answer is: 3^-6

since the exponent is negative, you put a 1 above the problem, making it a fraction: 1/3^-6

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Triangle ABC is to be dilated through point P with a scale factor of 3. How many units away from point A along ray PA will A’ be

drek231 [11]

Answer:

A' will be located 10 units from point A along ray PA

Step-by-step explanation:

we know that

The scale factor is equal to 3

To obtain PA', multiply PA by the scale factor

PA'=PA*3

PA=5 units

substitute

PA'=(5)*3=15 units

AA'=PA'-PA=15-5=10 units

therefore

A' will be located 10 units from point A along ray PA

3 0

3 years ago

Read 2 more answers

Matt started his own company where he rents used textbooks to struggling college students at multiple Universities for a low rat

lana66690 [7]

Answer:

a. Expected frequency of losses per semester = 0*0.08 + 5*0.16 + 10*0.28 + 15*0.32 + 20*0.14 + 25*0.02

Expected frequency of losses per semester = 11.7 losses per semester

b. Variance = (0-11.7)²*0.08 + (5-11.7)²*016 + (10-11.7)²*0.28 + (15-11.7)²*0.32 + (20-11.7)²*0.14 + (15-11.7)²*0.02

Variance = 10.9512 + 7.1824 + 0.8092 + 3.7848 + 9.6446 + 3.5378

Variance = 35.61

c. As losses equal $60, expected losses per semester = 11.7*$60 = $702

d. Expected losses of all textbooks per semester = 250*11.7*$60 = $175,500

7 0

3 years ago

for the data values below construct a 95 confidence interval if the sample mean is known to be 12898 and the standard deviation

Volgvan

Answer:

A 95% confidence interval for the population mean is [3315.13, 22480.87] .

Step-by-step explanation:

We are given that for quality control purposes, we collect a sample of 200 items and find 24 defective items.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample proportion of defective items = 12,898

s = sample standard deviation = 7,719

n = sample size = 5

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used a One-sample t-test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.776 < $t_4$ < 2.776) = 0.95 {As the critical value of t at 4 degrees of

freedom are -2.776 & 2.776 with P = 2.5%}

P(-2.776 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.776) = 0.95

P( $-2.776 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.776 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.776 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.776 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-2.776 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.776 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $12,898-2.776 \times {\frac{7,719}{\sqrt{5} } }$ , $12,898+2.776 \times {\frac{7,719}{\sqrt{5} } }$ ]

= [3315.13, 22480.87]

Therefore, a 95% confidence interval for the population mean is [3315.13, 22480.87] .

5 0

4 years ago

Can someone’s please help me? (Ignore the work)

Zinaida [17]

Answer:

a^14b^12

Step-by-step explanation:

okay so lets distribute the 2

so you get -a^6b^10 and a^8b^2

add

7 0

4 years ago

Use a negative factor to factor the expression - 7a+49b - 35

Helen [10]

Answer:

using a negative facto to factor the expression will be:

- 7a+49b - 35 = -7(a-7b+5)

Step-by-step explanation:

Given the expression

- 7a+49b - 35

Rewrite -35 as 5 · 7

Rewrite 49 as 7 · 7

= -7a + 7 · 7b - 5 · 7

as -7 is the common factor, so factoring out

= -7(a-7b+5)

Thus, using a negative facto to factor the expression will be:

- 7a+49b - 35 = -7(a-7b+5)

6 0

3 years ago