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3 years ago

Can you help me with this answer please

Mathematics

1 answer:

Andreyy893 years ago

4 0

Answer:

it's the second option. the second box is the answer. hope this helps

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Simplify (2 {sqrt 5}+ 3 {sqrt 7})^2. Show your work. Justify each step.

White raven [17]

(2√5 + 3(√7))^2
(2√5 + 3(√7))(2√5 + 3(√7))
4*5 + 6√35 + 6√35 + 9*7
20 + 12√35 + 63
20 + 63 + 12√35
83 + 12√35

4 0

4 years ago

Fourteen thousand seven hundred ninety three in standard form

NeTakaya

Answer:

14,793

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Last year direct marketing had $122,222 in sales. This year direct marketing's sales are down by 9%. What are direct marketings

Mashutka [201]

Answer:

$111222.02

Step-by-step explanation:

This year = Last year * (100%-9%)

This year = 122222 * 91% = 111222.02

7 0

2 years ago

Yo guys plz help me with this i need it for my homework

Vanyuwa [196]

Answer: For a is 19/15 or 1 4/15

for b I have no clue

Step-by-step explanation: add 3/5 and 2/3

you will get 19/15. In mixed fraction is 1 4/15

4 0

3 years ago

Read 2 more answers

Write the equation of a circle for which the endpoints of a diameter are (-2,-2) and (4,-10)

Maurinko [17]

Answer:

Therefore the required Equation of Circle

$x^{2}+y^{2}-2x+12y+12=0$

Step-by-step explanation:

Given:

End point of Diameter be

point A( x₁ , y₁) ≡ ( -2 ,-2 )

point B( x₂ , y₂) ≡ ( 4 , -10 )

To Find:

Equation of a circle =?

Solution:

When end points of the Diameter are A( x₁ , y₁) , B( x₂ , y₂). then the Equation of Circle is given as

$(x-x_{1})(x-x_{2})+(y-y_{1})(y-y_{2})=0$

Substituting the end point are

$(x-(-2))(x-4)+(y-(-2))(y-(-10))=0\\(x+2))(x-4)+(y+2))(y+10))=0\\$

Applying Distributive Property we get

$x^{2} -2x-8+y^{2}+12y+20 =0\\\\x^{2}+y^{2}-2x+12y+12=0$

Therefore the required Equation of Circle

$x^{2}+y^{2}-2x+12y+12=0$

6 0

3 years ago