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3 years ago

What is the difference of 35- (-8)

Mathematics

2 answers:

Dennis_Churaev [7]3 years ago

6 0

35-(-8)=35+8=43

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Scilla [17]3 years ago

4 0

Answer:

43

Solution:

You take 35 and add 8, this should get you the answer 43.

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Solve for the value of X pleassee

bulgar [2K]

Answer:

188

Step-by-step explanation:

SR and ST are equal in length so the arc SR and arc ST also have same measurement

since the perimeter of the circle is equal to 360 and arc RT is given as 64

x = (360 - 64) / 2

x = 188

3 0

3 years ago

The value of x is ___<br> °, and the value of y is

PtichkaEL [24]

Answer:

y=50

x=60

Step-by-step explanation:

x= 180-(50+70)

x=60

y=50

4 0

3 years ago

Read 2 more answers

Ralph bought a computer monitor with an area of 384 square inches. The length of the monitor is six times the quantity of five l

Lynna [10]

Answer:

eh width = 103.5 inches

Step-by-step explanation:

x = width

Length = (x/2 - 5 )*6

so 384=x+3x-30

414=4x

x=414/4=103.5 inches

5 0

3 years ago

A quadratic rule for a particular parabola is of the form y = ax^2 + bx. The parabola passes through with the coordinates (-1, 4

Scilla [17]

Answer:

y = (4/7)x² - (24/7)(x)

Step-by-step explanation:

4 = a(-1)² + b(-1)

4 = a - b

0 = a(6)² + b(6)

36a + 6b = 0

b = -6a

4 = a - (-6a)

7a = 4

a = 4/7

b = -24/7

y = (4/7)x² - (24/7)(x)

6 0

4 years ago

Need help simplifying this

diamong [38]

The simplified answer is $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$ .

<u>Step-by-step explanation:</u>

$$\frac{3 y+2 x}{z+2 x}-\frac{2 y-3 x}{3 x+y}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}$

To add or subtract denominators of the fraction must be same.

If it is not the same, we must take LCM of the denominators. and so we can add the fractions.

To make the denominator same multiply the 1st term $(\frac{3x+y}{3x+y})$ and 2nd term by $(\frac{z+2x}{z+2x})$

= $\frac{(3 y+2 x)(3 x+y)}{(z+2 x)(3 x+y)}-\frac{(2 y-3 x)(z+2 x)}{(3 x+y)(z+2 x)}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}$

LCM of the denominators is 6x²+ 3xz + 2xy +yz.

Multiply the factors in the numerator.

= $\frac{\left(6 x^{2}+3 y^{2}+11 x y\right)}{(z+2 x)(3 x+y)}-\frac{\left(2 y z+4 x y-3 x z-6 x^{2}\right)}{(3 x+y)(z+2 x)}-\frac{2 z y+6 x z}{6 x^{2}+3 x z+2 x y+y z}$

Now, the denominators are same, you can subtract it.

= $\frac{\left(6 x^{2}+6 x^{2}+11 x y-4 x y-2 y z-2 y z+3 x z-6 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

= $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

Thus the simplified solution is $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

4 0

3 years ago