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Misha Larkins [42]
3 years ago
13

What's the percent decrease for 3 to .5

Mathematics
1 answer:
In-s [12.5K]3 years ago
6 0
The percent decrease for 3 to .5 is 83.33%
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The quotient of a number and three, increased by one <br><br><br> Using the variable N
solniwko [45]
N÷3+1 or can be stated as 3÷n+1

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3 years ago
Performance Task A. Directions: Solve the problem and answer the following questions. Renz' family attended a pool party. The po
dezoksy [38]

Answer: 144 meters

Step-by-step explanation: area of circle = r^2

6^2 = 36 = 144 Meters given = 4

radius of pool is 6 meters

diameter of pool is 12 meters

= 4

area of circle = r^2

area of swimming pool is 144 meters

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1 year ago
Cual es la fraccion equivalente de 105/275
xxMikexx [17]

Answer:

21/55

Step-by-step explanation:

dividamos por 5

= 21/55

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2 years ago
Can someone please answer this !?!!
snow_tiger [21]

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4 0
3 years ago
Read 2 more answers
The attention span of children (ages 3 to 5) is claimed to be Normally distributed with a mean of 15 minutes and a standard devi
Agata [3.3K]

Answer:

If the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 15 minutes

Sample size, n = 10

Alpha, α = 0.05

Population standard deviation, σ = 4 minutes

First, we design the null and the alternate hypothesis

H_{0}: \mu = 15\text{ minutes}\\H_A: \mu > 15\text{ minutes}

Since the population standard deviation is given, we use one-tailed z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Now, z_{critical} \text{ at 0.05 level of significance for one tail} = 1.64

Thus, we would reject the null hypothesis if the z-statistic is greater than this critical value.

Thus, we can write:

z_{stat} = \displaystyle\frac{\bar{x} - 15}{\frac{4}{\sqrt{10}} } > 1.64\\\\\bar{x} - 15>1.64\times \frac{4}{\sqrt{10}}\\\bar{x} - 15>2.07\\\bar{x} > 15+2.07\\\bar{x} > 17.07

Thus, the decision rule would be if the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.

6 0
3 years ago
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