Answer:
23.5 in
Step-by-step explanation:
To find the length of HJ in triangle GHJ, create <u>three equations</u> using the given information, then solve simultaneously.
<u>Equation 1</u>
HJ is two inches longer than GH:
⇒ HJ = GH + 2
<u>Equation 2</u>
GJ is 17 inches shorter than the sum of HJ and GH:
⇒ GJ + 17 = HJ + GH
<u>Equation 3</u>
The perimeter of ΔGHJ is 73 inches:
⇒ HJ + GH + GJ = 73
<u>Substitute</u> Equation 1 into <u>Equation 2</u> and isolate GJ:
⇒ GJ + 17 = GH + 2 + GH
⇒ GJ + 17 = 2GH + 2
⇒ GJ = 2GH - 15
<u>Substitute</u> Equation 1 into <u>Equation 3</u> and isolate GJ:
⇒ GH + 2 + GH + GJ = 73
⇒ 2GH + GJ = 71
⇒ GJ = 71 - 2GH
<u>Equate</u> the two equations where GJ is the subject and <u>solve for GH</u>:
⇒ 2GH - 15 = 71 - 2GH
⇒ 4GH = 86
⇒ GH = 21.5
<u>Substitute</u> the found value of GH into <u>Equation 1</u> and solve for HJ:
⇒ HJ = 21.5 + 2
⇒ HJ = 23.5
It usually works to use the formula for the area of a trapezoid.
A = (1/2)×(b₁ +b₂)×h
where b₁ and b₂ are the lengths of the parallel bases, and h is the height (the perpendicular distance between the bases)
_____
This is one of several area formulas it pays to memorize.
Answer:
30
Step-by-step explanation:
He is walking 3 dogs an hour
