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natka813 [3]
3 years ago
12

assume the situation can be exposed as a linear cost, find the cost function, fixed cost is $100, 40 items cost 1,200 to produce

: linear cost is C(x)= ________.
Mathematics
1 answer:
alexira [117]3 years ago
7 0
C(x) = 1200(40) + 100
or
       = mx+c
where m = 1200, x = 40, y = 100

hope it helped,
click thx if it did.
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dusya [7]

For this case we have a function of the form:

n (t) = n0 * (b) ^ t

Where,

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b: growth rate

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The third side is described in relation to one of the
Ann [662]

<u>Complete Question: </u>

An isosceles triangle has two sides of equal length. The third side is 5 less than twice the length of one of the other sides. If the perimeter of the triangle is 23 cm, what is the length of the third side The third side is described in relation to one of the equal sides, so let x = the length of one of the equal sides. Which equation models the problem?

O x + x + (5 – 2 x) = 23

O x + x + (2 x – 5) = 23

O x + x + (2 x + 5) = 23

O X + (2 x - 5) + (2 x - 5) = 23

<u>Answer: </u>

The equation models the problem is x + x + (2 x – 5) = 23

<u>Step-by-step explanation:</u>

Given:

An isosceles triangle has two sides of equal length, so let x = the length of one of the equal sides .

The third side is 5 less than twice the length of one of the other sides. So, the third side is described as 2 x - 5.

The perimeter is the sum of the side lengths and given it as 23. Therefore, form the equation as below,

                Perimeter = x + x + (2 x-5)

Given perimeter of triangle = 23 cm. Hence,

                x + x + (2 x-5) = 23

The above equation models the given problem.

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4 years ago
Help out I need answer 29 points
VLD [36.1K]

Answer:

Option 2

Step-by-step explanation:

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5 0
3 years ago
2. A triangular pyramid begins with these coordinates:
mario62 [17]
1. <span>The yz-plane is the plane x = 0.  </span>
So, The general rule of reflection over the yz- plane is <span>(x,y,z) →(−x,y,z)
</span>
===========================================

<span>2. Applying the rule found in (1)
</span>
<span>the new points of the shape after this reflection will be
</span>
P(–1, 2, 0)  ⇒⇒⇒ <span>P'(1, 2, 0)
</span>Y(2, 3, 0)    <span>⇒⇒⇒ Y'(-2, 3, 0)
</span> R(–3, 4, 0)  ⇒⇒⇒ <span>R'(3, 4, 0)
</span> A(–2, 1, 5)  ⇒⇒⇒ A'(2, 1, 5)
=============================================

3. Applying the transformation rule <span>(x, y, z) → (x + 2, y + 4, z – 3)
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<span />to the points from number 2

<span>P'(1, 2, 0)  ⇒⇒⇒ P" (3 , 6 , -3 )
</span><span>Y'(-2, 3, 0) ⇒⇒⇒ Y" (0 , 7 , -3)
</span><span>R'(3, 4, 0)  ⇒⇒⇒ R" ( 5 , 8 , -3)
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What is 1000 times 20089
Dvinal [7]

Answer:

20089000

Step-by-step explanation:

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