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Sergio039 [100]
2 years ago
9

Khushali selects three different numbers from the set

Mathematics
1 answer:
Maslowich2 years ago
3 0

Answer:

The sample space for given condition is

(1,8),(2,8),(3,8),(4,8),(5,8),(6,8),(7,8)

(1,7),(2,7),(3,7),(4,7),(5,7),(6,7)

(1,6),(2,6),(3,6),(4,6),(5,6)

(1,5),(2,5),(3,5),(4,5)

(1,4),(2,4),(3,4)

(1,3),(2,3)

(1,2)

Number of sample space is 28.

Number of sample space where the sum of two numbers is more than 13 is 2((6,8),(7,8)). Therefore the probability is

28

2

=

14

1

Step-by-step explanation:

please thank to all my answer and please mark as brilliant

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The volume of a rectangular prism is b3 + 8b2 + 19b + 12 cubic units, and its height is b + 3 units. The area of the base of the
omeli [17]
Given:

The volume of the rectangular prism is 

b^{3}+8 b^{2} +19b+12,

the height is h=(b+3)

1. The volume of a rectangular prism is (base area)*height

also, notice that the volume is a third degree polynomial, the height is a 1st degree polynomial, so the base area must be a 2nd degree polynomial, whose coefficients we don't know yet.
Let this quadratic polynomial be (mb^{2}+nb+k)

 
2

b^{3}+8 b^{2} +19b+12=(mb^{2}+nb+k)*(b+3)


notice that  b^{3} is the product of the largest 2 terms: mb^{2} and b, so m must be 1

also, notice that 12 is the product of the constants, k and 3

so k*3=12, this means k=4

3
we write the above equality again:

b^{3}+8 b^{2} +19b+12=(b^{2}+nb+4)*(b+3)


(b^{2}+nb+4)(b+3)= b^{3}+3 b^{2} +nb^{2}+3nb+4b+12

== b^{3}+(n+3)b^{2}+(3n+4)b+12


4
now compare the coefficient with the left side:

8 b^{2}=(n+3)b^{2}

8=n+3

n=5


substituting n=5: 

the base area is b^{2}+5b+4

Answer: b^{2}+5b+4


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