the answer for the second problem is x=99 degrees and y= 261 degrees
dunno the first problem :/
Parallel lines are a pair of lines that do not intersect
Therefore this is not an example of parallel lines because the lines intersect
The answer is C
9514 1404 393
Answer:
geometric sequence
Step-by-step explanation:
The terms of the sequence have a common ratio of -12/3 = -4, so the sequence is geometric. The general term is ...
an = 3(-4)^(n-1)
so the sum can be written as ...
(Note the summation starts at n=0, corresponding to a first term of 3.)
Answer:
(-10,-10)
Step-by-step explanation:
9x-9y=0
3x-4y=10
In elimination, we want both equations to have the same form and like terms to be lined up. We have that. We also need one of the columns with variables to contain opposites or same terms. Neither one of our columns with the variables contain this.
We can do a multiplication to the second equation so that the first terms of each are either opposites or sames. It doesn't matter which. I like opposites because you just add the equations together. So I'm going to multiply the second equation by -3.
I will rewrite the system with that manipulation:
9x-9y=0
-9x+12y=-30
----------------------Add them up!
0+3y=-30
3y=-30
y=-10
So now once you find a variable, plug into either equation to find the other one.
I'm going to use 9x-9y=0 where y=-10.
So we are going to solve for x now.
9x-9y=0 where y=-10.
9x-9(-10)=0 where I plugged in -10 for y.
9x+90=0 where I simplified -9(-10) as +90.
9x =-90 where I subtracted 90 on both sides.
x= -10 where I divided both sides by 9.
The solution is (x,y)=(-10,-10)
The first word of the question is cut out of the picture, so we don't exactly know what the assignment is. But we can see that the graph of f(x) will do something weird when x=-3, because the denominator will be zero, and division by zero doesn't even have a definition or meaning. Just for fun, you should go ahead and calculate the numerator when x=-3, and that totally blows your mind, because the numerator is zero too. So you've got. f(-3)= 0/0 , and I can pretty much guarantee that you won't be able to plot that point anywhere on the graph. (I'm pretty sure that f(-3) is actually going to turn out to be -13, but even if I'm correct, you probably haven't learned that little calculus trick yet, so don't worry about it. As far as you're concerned, f(-3) is 0/0, and can't be plotted.)
