You can get a vertical asymptote at x=1 using y = 1/(x-1)
You can generate a hole at x=3 by multiplying by (x - 3/(x - 3) which is undefined at x=3 but otherwise equals 1
You can move the horizontal asymptote up to y=2 by adding 2
y = (x - 3)/((x - 1)(x - 3)) + 2
Answer:
Find the number in the hundred place
3
and look one place to the right for the rounding digit
2
. Round up if this number is greater than or equal to
5
and round down if it is less than
5
.
ANSWER: 2300
Step-by-step explanation:
Answer:
7cm
Step-by-step explanation:
One side of a square is increased by 8 cm, let us say the length got increased by 8 cm. So we have length of x + 8 cm
An adjacent side, the width, decreased by 2 cm. So we have width of x - 2cm
Perimeter of rectangle = 2(length + width)
40 = 2( (x + 8) + ( x - 2) )
40 = 2( 2x + 6)
40 = 4x + 12
28 = 4x
x = 7 cm
That is 7 cm of the length of the side of the square
1.
If no changes are made, the school has a revenue of :
625*400$/student=250,000$
2.
Assume that the school decides to reduce n*20$.
This means that there will be an increase of 50n students.
Thus there are 625 + 50n students, each paying 400-20n dollars.
The revenue is:
(625 + 50n)*(400-20n)=12.5(50+n)*20(20-n)=250(n+50)(20-n)
3.
check the options that we have,
a fee of $380 means that n=1, thus
250(n+50)(20-n)=250(1+50)(20-1)=242,250 ($)
a fee of $320 means that n=4, thus
250(n+50)(20-n)=250(4+50)(20-4)=216,000 ($)
the other options cannot be considered since neither 400-275, nor 400-325 are multiples of 20.
Conclusion, neither of the possible choices should be applied, since they will reduce the revenue.
Answer:
whats the question?
Step-by-step explanation:
