Answer:
15 is right ans
Step-by-step explanation:
Answer:
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Step-by-step explanation:
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Answer:
Step-by-step explanation:
a. The hypothesis test is one tailed_____ test.
(Because we check whether sample weight is greater than hence one tailed or right tailed)
The test statistic follows a __t___ distribution.(Because only sample std deviation s is known)
The value of the test statistic is___Mean difference/Std error =
__
b. df = 66
Reject H0 if t ≥ 1.668
c. The p-value is_____0.059444
d. Using the critical value approach, the null hypothesis is _accepted____, because __t <1.668___ Using the p-value approach, the null hypothesis is__accepted___, because__p value <0.05 our significance level.___ Therefore, you __may___ conclude that the mean weight of the airline's passengers' carry-on items has increased after the implementation of the checked-bag fee.
The percentage of tardiness among the 102 pupils is 2.94.
<h2>Calculation of the percentage</h2>
According to the query,
Course A: Total number of students = 102
Number of tardy students = 3
Percent of students tardy in course A = (number of tardy students/total
number of students) * 100
=(3/102)*100
= 2.941
≈2.94
In case of course B: Total number of students = 85 & tardy student = 5
So, the percent of tardy student = (5/85)*100 = 5.88 %
Therefore, it is concluded that the percentage of student tardiness in course A is 2.94.
Learn more about the percentage here:
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Answer:
2 and 24
Step-by-step explanation:
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