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abruzzese [7]
3 years ago
7

Please help if you want BRIANLEIST!!

Mathematics
1 answer:
Bumek [7]3 years ago
6 0

Answer:

9/9 × 7 is equal to 7

9/9 × 7 =

9/9 × 7/1 =

9 × 7 = 63

9 × 1 = 9

63/9 ÷ 9 = 7

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5/6 as a percent then rounded to the nearest hundred percent
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Answer:

Step-by-step explanation:

83.33To do that we divide 5 / 6, which gives us approximately 0.83333, now we multiply it by 100 since percentages are parts of 100.

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What is the probability that the first spinner will land on B, the second spinner will land on 3, and the third spinner will lan
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3 1/3 this is all about fractions
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S. At Food Lion, 28 of every 35 jars of peanut butter on the shelves are creamy peanut butter. What percent of the jars of peanu
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7/35 or 20% of the jars are not creamy

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What is the equation of a line that passes through the point (8, 1) and is perpendicular to the line whose equation is y=−2/3x+5
Anuta_ua [19.1K]

Answer:

y = \frac{3}{2} x-11

Step-by-step explanation:

We are to find the equation a line that passes through the point (8, 1) and which is perpendicular to a line whose equation isy = - \frac{2}{3} x+5.

We know that the slope of line which is perpendicular to another line is the negative reciprocal of the slope of the other line so it will be \frac{3}{2}.

Then, we will find the y-intercept of the line using the standard equation of a line:

y=mx+c

1=\frac{3}{2} (8)+c

c=-11

Therefore, the equation of the line will be y = \frac{3}{2} x-11.


7 0
3 years ago
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{4x-2y+5z=6 <br> {3x+3y+8z=4 <br> {x-5y-3z=5
lesya692 [45]

There are three possible outcomes that you may encounter when working with these system of equations:


  •    one solution
  •    no solution
  •    infinite solutions

We are going to try and find values of x, y, and z that will satisfy all three equations at the same time. The following are the equations:

  1. 4x-2y+5z = 6
  2. 3x+3y+8z = 4
  3. x-5y-3z = 5

We are going to use elimination(or addition) method

Step 1: Choose to eliminate any one of the variables from any pair of equations.

In this case it looks like if we multiply the third equation by 4 and  subtracting it from equation 1, it will be fairly simple to eliminate the x term from the first and third equation.

So multiplying Left Hand Side(L.H.S) and Right Hand Side(R.H.S) of 3rd equation with 4 gives us a new equation 4.:

4. 4x-20y-12z = 20      

Subtracting eq. 4 from Eq. 1:

(L.HS) : 4x-2y+5z-(4x-20y-12z) = 18y+17z

(R.H.S) : 20 - 6 = 14

5. 18y+17z=14

Step 2:  Eliminate the SAME variable chosen in step 2 from any other pair of equations, creating a system of two equations and 2 unknowns.

Similarly if we multiply 3rd equation with 3 and then subtract it from eq. 2 we get:

(L.HS) : 3x+3y+8z-(3x-15y-9z) = 18y+17z

(R.H.S) : 4 - 15 = -11

6. 18y+17z = -11

Step 3:  Solve the remaining system of equations 6 and 5 found in step 2 and 1.

Now if we try to solve equations 5 and 6 for the variables y and z. Subtracting eq 6 from eq. 5 we get:

(L.HS) : 18y+17z-(18y+17z) = 0

(R.HS) : 14-(-11) = 25

0 = 25

which is false, hence no solution exists



3 0
3 years ago
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