1−w−w2=64
Step 1: Simplify both sides of the equation.
−w2−w+1=64
Step 2: Subtract 64 from both sides.
−w2−w+1−64=64−64
−w2−w−63=0
For this equation: a=-1, b=-1, c=-63
−1w2+−1w+−63=0
Step 3: Use quadratic formula with a=-1, b=-1, c=-63.
w=
−b±√b2−4ac
/2a
w=
−(−1)±√(−1)2−4(−1)(−63)
/2(−1)
w=
1±√−251/
−2
Answer:
No solution
Step-by-step explanation:
As 6x on lhs and 2×3x on the rhs are equal and cancel each other
Answer:
Step-by-step explanation:
Hello,
degree 5
4 is a zero of multiplicity 3 -> (x-4)^3 is a factor
-4 is the only other zero, so the multiplicity is 5-3=2 -> (x+4)^2 is a factor
leading coefficient is 4 so we can write

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