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3 years ago

A new pair of sneakers costs $70 now. What is the cost of the shoes 5 years from now if the price increases 8% per year?

Mathematics

2 answers:

Ilya [14]3 years ago

8 0

D. 109$ if it increases 8% a year

lesantik [10]3 years ago

7 0

Answer:

Option A. $103.

Step-by-step explanation:

A new pair of sneakers cost $70 now.

The cost of the shoes after 5 years if the price increases 8% per year.

We will solve it by this formula

$A=P(1+\frac{r}{n})^{nt}$

Where A = final amount after t years

r = rate of increase

n = compounded in a year

t = time in years

$A=70(1+\frac{0.08}{1})^{(1)(5)}$

$A=70(1+0.08)^{5}$

A = 70(1.08)⁵

A = 70 × 1.46932808

A = 102.8529 ≈ $103

Option A $103 is the answer.

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2 years ago

Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 141 millimeters,

tiny-mole [99]

Answer:

Probability that the sample mean would be greater than 141.4 millimetres is 0.3594.

Step-by-step explanation:

We are given that Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 141 millimetres, and a standard deviation of 7.

A random sample of 39 steel bolts is selected.

Let $\bar X$ = sample mean diameter

The z score probability distribution for sample mean is given by;

Z = $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } } }$ ~ N(0,1)

where, $\mu$ = population mean diameter = 141 millimetres

$\sigma$ = standard deviation = 7 millimetres

n = sample of steel bolts = 39

Now, Percentage the sample mean would be greater than 141.4 millimetres is given by = P( $\bar X$ > 141.4 millimetres)

P( $\bar X$ > 141.4) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } } }$ > $\frac{141.4-141}{\frac{7}{\sqrt{39} } } }$ ) = P(Z > 0.36) = 1 - P(Z $\leq$ 0.36)