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svetoff [14.1K]
3 years ago
6

Use the midpoint formula to find the midpoint of a line (2,9) and (4,8)

Mathematics
1 answer:
Sindrei [870]3 years ago
3 0

Answer:

hope this helps you!

Step-by-step explanation:

(3, 8.5) is the answer

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Highest common factor of 135 and 180
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<span>the highest common factor is forty-five</span>
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Use the discriminant to describe the roots of each equation. Then select the best description. 3x2 - 10 = 0. A) Double root B) R
Mademuasel [1]

1. discriminant = b^2 - 4ac = (-5)^2 - (4 x 1 x 7) = 25 - 28 = -3  [imaginary root]


2. discriminant = (-5)^2 - (4 x 1 x -4) = 25 - (-16) = 25 + 16 = 41  [real and irrational root]


3. discriminant = (8)^2 - (4 x 16 x 1) = 64 - 64 = 0    [double root]


Read more on Brainly.com - brainly.com/question/1698047#readmore




hope it helps

4 0
2 years ago
Read 2 more answers
Please help 10 point reward​
LekaFEV [45]

ANSWER:    I can give you the steps to figure out this question.

1  if it is starting at the 6 on the y axis, then just do up 1 over 1 until you get to the 10

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4 0
3 years ago
the numerator is the blank number in a fraction while the denominator is the blank number in a fraction
Pie

The numerator is the top number in a fraction, while the denominator us the bottom number in a fraction.

8 0
3 years ago
The heights of young women aged 20 to 29 follow approximately the N(64, 2.7) distribution. Young men the same age have heights d
murzikaleks [220]

Answer: 10.703%

Step-by-step explanation:

Let minimum height of the tallest 25% of young women be M.

Let Q be the random variable which denotes the height of young women.

Therefore, Q – N(64,2.70)

Now, P(Q˂M) = 1-0.25

i.e. P[(Q-64)/2.7 ˂ (M-64)/2.7] = 0.75

I.e. ф-1 [(M-64)/2.7] = 0.75 i.e. (M-64)/2.7 = ф-1 (0.75) = 0.675 i.e. M = 65.8198 inches

Let R be the random variable denoting the height of young men

Therefore, R – N (69.3, 2.8)

i.e. (R-69.3)/2.8 – N(0,1)

therefore the probability required = P(R ˂65.8198) = P[(R-69.3)/2.8 ˂ (65.8198 – 69.3)/2.8]

this gives P[(R-69.3)/2.8 ˂] = ф (-1.2429) = 0.107033

From this, the percentage of young men shorter than the shortest amongst the tallest 25% of young women is 10.703%

4 0
3 years ago
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