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2 years ago

Which division equation is shown by the area model. Show work

Mathematics

1 answer:

ad-work [718]2 years ago

8 0

You need to show me the model, so I can answer the question.

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Which of the following is the closest to 15%? A. 1/7 B. 1/5 c. 1/4 d 1/3

Solnce55 [7]

Answer:

15%=0.15

1÷7=0.14

1÷5=0.2

1÷4=0.25

1÷3=0.33

Step-by-step explanation:

1/7

5 0

3 years ago

Read 2 more answers

The average yearly temperature T in degrees for Newport, Oregon is given by: |T−55|≤10 Find the average temperature range in deg

Nata [24]

Good evening

The absolute value has the following property:

$|x|\leq a\iff -a\leq x\leq a$

Apllying:

$|T-55| \leq 10 \iff -10\leq T - 55 \leq 10\\ \\ -10 + 55 \leq T -55 + 55 \leq 10 + 55\\ \\ \boxed{45\leq T \leq 65}$

The average temperature range is between 45 and 65 degrees.

8 0

3 years ago

Consider the inequality -20.2 > 0y. Which of the following must be true? Check all that apply. You cannot divide by zero. The

Katarina [22]

Answer:

You can not divide by zero.

The inequality is equivalent to - 20.2 > 0 which is false.

Step-by-step explanation:

We can not divide both sides by zero, because if we divide both sides by zero, then the inequality becomes

$- \frac{20.2}{0} > y$

⇒ - ∞ > y, which is not possible.

Again, the given inequality is - 20.2 > 0 × y.

We have to multiply y with zero and a product of zero with any term is also zero.

Hence, the inequality becomes - 20.2 > 0.

Therefore, the inequality is equivalent to - 20.2 > 0 which is false. (Answer)

4 0

2 years ago

Read 2 more answers

A) Use the method of cylindrical shells to find the volume of the solid obtained by rotating the region bounded by the given cur

Leno4ka [110]

(a) See the attached sketch. Each shell will have a radius y chosen from the interval [2, 4], a height of x = 2/y, and thickness ∆y. For infinitely many shells, we have ∆y converging to 0, and each super-thin shell contributes an infinitesimal volume of

2π (radius)² (height) = 4πy

Then the volume of the solid is obtained by integrating over [2, 4]:

$\displaystyle 4\pi \int_2^4 y\,\mathrm dy = 2\pi y^2\bigg|_{y=2}^{y=4} = 2\pi (4^2-2^2) = \boxed{24\pi}$

(b) See the other attached sketch. (The text is a bit cluttered, but hopefully you'll understand what is drawn.) Each shell has a radius 9 - x (this is the distance between a given x value in the orange shaded region to the axis of revolution) and a height of 8 - x ³ (and this is the distance between the line y = 8 and the curve y = x ³). Then each shell has a volume of

2π (9 - x)² (8 - x ³) = 2π (648 - 144x + 8x ² - 81x ³ + 18x ⁴ - x ⁵)

so that the overall volume of the solid would be

$\displaystyle 2\pi \int_0^2 (648-144x+8x^2-81x^3+18x^4-x^5)\,\mathrm dx = \boxed{\frac{24296\pi}{15}}$