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3 years ago

Someone please help

Mathematics

1 answer:

kumpel [21]3 years ago

3 0

Answer:

Step-by-step explanation: For question 33 you have : (3x+3)+(6x+6)+90........ =180(sum of angles in a triangle is 180).

Question 34: (x+78)+(x+70)+44=180.....(same reason)

Question 35: (x+51)+(x+61)+90=180.....(same reason)

Question 36:(x+71)+(x+41)+90=180....(same reason).

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3 years ago

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-Dominant- [34]

3.28·3 = 9.84 is the same as:
3.28+3.28+3.28 = 9.84

Hope this helped! Good luck!

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Rama09 [41]

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D(x)=(x^2-12x+20)/(3x)

krok68 [10]

Answers:

Vertical asymptote: x = 0

Horizontal asymptote: None

Slant asymptote: (1/3)x - 4

Explanation:

d(x) = $\frac{x^{2}-12x+20}{3x}$

= $\frac{(x-2)(x - 10)}{3x}$

Discontinuities: (terms that cancel out from numerator and denominator):

Nothing cancels so there are NO discontinuities.

Vertical asymptote (denominator cannot equal zero):

3x ≠ 0

÷3 ÷3

x ≠ 0

So asymptote is to be drawn at x = 0

Horizontal asymptote (evaluate degree of numerator and denominator):

degree of numerator (2) > degree of denominator (1)

so there is NO horizontal asymptote but slant (oblique) must be calculated.

Slant (Oblique) Asymptote (divide numerator by denominator):

(1/3)x - 4
3x) x² - 12x + 20
x²
-12x
-12x
20 (stop! because there is no "x")

So, slant asymptote is to be drawn at (1/3)x - 4

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How many six-digit odd numbers are possible if the left digit cannot be zero?

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