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2 years ago

Round 1,129.872 to 2 decimal places

Mathematics

2 answers:

Novay_Z [31]2 years ago

6 0

It's 1129.87 the two rounds down

gulaghasi [49]2 years ago

4 0

The answer is 1,129.87
If you need to round to 2 decimal places you want two numbers after the decimal point.

<em>If you were to have the number 1,129.875 and you wished to round to two decimal places the third number after the decimal tells you whether it will round down or up. If the third number after the decimal point is equal to 5 or more the number before it (in this case the second number after the decimal point) will increase by one. For this example 1,129.875 to two decimal places is 1,129.88. </em>

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n200080 [17]

K can be 10,11,14,25

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The price of one share of stock in BadInvestment.com plunged 14 points in 4 weeks. Find the average change in stock price per da

mariarad [96]

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Step-by-step explanation:

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2 years ago

4. What is the value of the expression 72 + (33 + 12) 23 a. 3 b. 8 C. 9 d. 11

jeyben [28]

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2 years ago

a boat travels upstream on the allegheny river for 2 hours. the return trip only takes 1.7 hours because the boat travels 2.5 mi

Gre4nikov [31]

To solve this we are going to use the speed equation: $S= \frac{d}{t}$
where
$S$ is speed
$d$ is distance
$t$ time

We know from our problem that the upstream trip takes 2 hours, so $t_{u}=2$ . We also know that the downstream trip takes 1.7 hours, so $t_{d}=1.7$ . Notice that the distance of both trips is the same, so we are going to use $d$ to represent that distance.
Now, lets use our equation to relate the quantities:

For the upstream trip:
$S_{u}= \frac{d}{t_{u} }$
$S_{u}= \frac{d}{2}$ equation (1)

For the downstream trip:
$S_{d}= \frac{d}{t_{d} }$
$S_{d}= \frac{d}{1.7}$ equation (2)

We know that the boat travels 2.5 miles per hour faster downstream, so the speed of the boat upstream will be the speed of the boat downstream minus 2.5 miles per hour:
$S_{u}=S_{d}-2.5$ equation (3)

Replacing (3) in (1):
$S_{u}= \frac{d}{2}$
$S_{d}-2.5= \frac{d}{2}$ equation (4)

Solving for $d$ in equation (2):
$S_{d}= \frac{d}{1.7}$
$d=1.7S_{d}$ equation (5)

Replacing (5) in (4):
$S_{d}-2.5= \frac{d}{2}$
$S_{d}-2.5= \frac{1.7S_{d}}{2}$
$2(S_{d}-2.5)=1.7S_{d}$
$2S_{d}-5=1.7S_{d}$
$0.3S_{d}=5$
$S__{d}= \frac{5}{0.3}$
$S_{d}= \frac{50}{3}$ equation (6)

Replacing (6) in (5)
$d=1.7S_{d}$
$d=1.7( \frac{50}{3} )$
$d= \frac{85}{3}$ miles

We can conclude that the boat travel $\frac{85}{3}$ , which is approximately 28.3 miles, in one way.

5 0

2 years ago