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3 years ago

Round 1,129.872 to 2 decimal places

Mathematics

2 answers:

Novay_Z [31]3 years ago

6 0

It's 1129.87 the two rounds down

gulaghasi [49]3 years ago

4 0

The answer is 1,129.87
If you need to round to 2 decimal places you want two numbers after the decimal point.

If you were to have the number 1,129.875 and you wished to round to two decimal places the third number after the decimal tells you whether it will round down or up. If the third number after the decimal point is equal to 5 or more the number before it (in this case the second number after the decimal point) will increase by one. For this example 1,129.875 to two decimal places is 1,129.88.

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What is the probability of rolling an even number with one roll of a number cube?

oee [108]

Answer:

50% or 1/2

Step-by-step explanation:

There is an even amount of even and odd numbers on a number cube, therefor it is split half and half, giving you 50%.

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3 years ago

Figure A is translated 3 units right and 2 units up. The translated figure is labeled figure B. Figure B is reflected over the x

mojhsa [17]

Answer:

A Is congruent to B and B Is congruent to C

Step-by-step explanation:

Given Figures A, B and C on a coordinate plane with the coordinates below:

Triangle A has points (1, -2), (3, -2), (3, -5).

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3 years ago

Which answer will be greater explain 1/3÷5 or 5÷1/3

Illusion [34]

The answer is 5 divided by 1/3

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3 years ago

Read 2 more answers

16x^2 + 10x — 27 = -6x + 5 What are the solutions to this equation?

dexar [7]

Answer:

x=1 or x=−2

Step-by-step explanation:

16x2+10x−27=−6x+5

Step 1: Subtract -6x+5 from both sides.

16x2+10x−27−(−6x+5)=−6x+5−(−6x+5)

16x2+16x−32=0

Step 2: Factor left side of equation.

16(x−1)(x+2)=0

Step 3: Set factors equal to 0.

x−1=0 or x+2=0

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4 0

3 years ago

Suppose there is a pile of quarters, dimes, and pennies with a total value of $1.06. How much of each coin can be present wit

SpyIntel [72]

Hello,

I note (a,b,c) the result of a quarters, b dimes and c pennies:

2 solutions:
106=( 3, 3, 1)=( 1, 8, 1)

106=( 0, 0, 106) but : 100= 0*25+ 0*10+ 100
106=( 0, 1, 96) but : 100= 0*25+ 1*10+ 90
106=( 0, 2, 86) but : 100= 0*25+ 2*10+ 80
106=( 0, 3, 76) but : 100= 0*25+ 3*10+ 70
106=( 0, 4, 66) but : 100= 0*25+ 4*10+ 60
106=( 0, 5, 56) but : 100= 0*25+ 5*10+ 50
106=( 0, 6, 46) but : 100= 0*25+ 6*10+ 40
106=( 0, 7, 36) but : 100= 0*25+ 7*10+ 30
106=( 0, 8, 26) but : 100= 0*25+ 8*10+ 20
106=( 0, 9, 16) but : 100= 0*25+ 9*10+ 10
106=( 0, 10, 6) but : 100= 0*25+ 10*10+ 0
106=( 1, 0, 81) but : 100= 1*25+ 0*10+ 75
106=( 1, 1, 71) but : 100= 1*25+ 1*10+ 65
106=( 1, 2, 61) but : 100= 1*25+ 2*10+ 55
106=( 1, 3, 51) but : 100= 1*25+ 3*10+ 45
106=( 1, 4, 41) but : 100= 1*25+ 4*10+ 35
106=( 1, 5, 31) but : 100= 1*25+ 5*10+ 25
106=( 1, 6, 21) but : 100= 1*25+ 6*10+ 15
106=( 1, 7, 11) but : 100= 1*25+ 7*10+ 5
106=( 1, 8, 1) is good
106=( 2, 0, 56) but : 100= 2*25+ 0*10+ 50
106=( 2, 1, 46) but : 100= 2*25+ 1*10+ 40
106=( 2, 2, 36) but : 100= 2*25+ 2*10+ 30
106=( 2, 3, 26) but : 100= 2*25+ 3*10+ 20
106=( 2, 4, 16) but : 100= 2*25+ 4*10+ 10
106=( 2, 5, 6) but : 100= 2*25+ 5*10+ 0
106=( 3, 0, 31) but : 100= 3*25+ 0*10+ 25
106=( 3, 1, 21) but : 100= 3*25+ 1*10+ 15
106=( 3, 2, 11) but : 100= 3*25+ 2*10+ 5
106=( 3, 3, 1) is good
106=( 4, 0, 6) but : 100= 4*25+ 0*10+ 0

5 0

3 years ago