The expected value of health care without insurance is $437.25.
The expected value of health care with insurance is $1,636.40.
<h3>What are the expected values?</h3>
The expected values can be determined by multiplying the respective probabilities by its associated costs.
The expected value of health care without insurance = (1 x 0) + (0.32 x 1050) + (0.45 x $225) = $437.25.
The expected value of health care with insurance = (1 x 1580) + (0.32 x 75) + (0.45 x $72) = $1,636.40.
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Answer:
Ima guess c
Step-by-step explanation:
dont choose mines I guessed
The 90% , 99% confidence interval for the population mean is 32.145 < < 35.855 and 31.093 < < 36.907
<h3>What is Probability ?</h3>
Probability is the study of likeliness of an event to happen.
It is given that
Total Population = 50
Mean = 35
The confidence interval is given by
is the mean
z is the confidence level value
s is the standard deviation
n is the population width
(a) The 90% confidence interval for the population mean
90% = 0.05
Z = 1.64
34 1.64 * 8 / √50
34 1.855
32.145 < < 35.855
(b) The 99% confidence interval for the population mean
99% = 0.005
Z=2.57
34 2.57 * 8 / √50
34 2.907
31.093 < < 36.907
Therefore the confidence interval for population mean has been determined.
The complete question is
A simple random sample of 50 items from a population width =7 resulted in a sample mean of 35. If required, round your answers to two decimal places.
a. Provide a 90% confidence interval for the population mean
b. Provide a 99% confidence interval for the population mean
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Answer:true!!!
Step-by-step explanation:
B C D because you find it closer