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shusha [124]
3 years ago
9

Can I get some help somebody? reward brainiest

Mathematics
1 answer:
OLEGan [10]3 years ago
6 0

Answer:

Step-by-step explanation:

1). x² - 8x

  To convert this expression into a perfect square trinomial,

  x² - 2(4x) + 4² = (x - 2)²

  Therefore , 4² = 16 should be added.

  Option (4) is the answer.

2). x² + 2x = 3

   x² + 2(1)(x) = 3

   x² + 2(1)(x) + 1 = 3 + 1 [By adding 1 on both the sides]

   (x + 1)² = 4

    x + 1 = ±2

    x = -3, -1

   Option (1) is the answer.

3). 3x²- 18x = 21

    x² - 6x = 7

    x² - 2(3x) = 7

    x² - 2(3x) + 3² = 7 + 3²

    (x - 3)² = 7 + 9

    (x - 3)² = 16

     x - 3 = ±4

     x = -1, 7

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We are given the functions:

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<span>C (P) = 1.14 P                                      ---> 2</span>

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C (P) = 1.14 (0.75 d)

C (P) = 0.855 d

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<span>C [P (d)] = 0.855 d</span>

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A store sells 8 cans of nuts for $18. how much would it cost to buy 3 cans of nuts
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75 percent of 88 is the same as 60 percent of what number?
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To find this number we multiply 88 by 0.75. 
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Therefore, 60% of a certain number equals 66.
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Find the area of rectangle, where length is 15 cm and breadth is 7 cm.​
Varvara68 [4.7K]

Question :-

  • Find the Area of Rectangle , where the Lenght is 15 cm and its Breadth is 7 cm .

Answer :-

  • Area of Rectangle is 105 cm² .

\rule {195pt} {2pt}

Diagram :-

\sf{15 \: cm} \\ \quad \quad  \begin{gathered}\begin{gathered} \boxed{\begin{array}{c} \\   \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \\  \\  \\ \end{array}}  \:  \:  \sf {7 \: cm}\end{gathered}\end{gathered}

\rule {195pt} {2pt}

Solution :-

\quad \quad » As per the provided information in the given question, we have been given that the Length of Rectangle is 15 cm . It's Breadth is given as 7 cm . And, we have been asked to calculate the Area of Rectangle.

For calculating the Area of Rectangle , we will use the Formula :-

  • \sf {Area \: of \: Rectangle \: = \: Length \: \times \: Breadth}

Therefore , by Substituting the given values in the above Formula :-

\Longrightarrow \: \: \: \sf {Area \: of \: Rectangle \: = \: Length \: \times \: Breadth} \\

\Longrightarrow \: \: \: \sf {Area \: of \: Rectangle \: = \: 15 \: \times \: 7}

\Longrightarrow \: \: \: \sf {Area \: of \: Rectangle \: = \: 105}

Hence :-

  • Area of Rectangle = 105 cm² .

\underline {\rule {195pt} {4pt}}

Additional Information :-

\begin{gathered}\begin{gathered}\boxed{\begin{array}{c} \\ \underline{ { \textbf {\textsf \red{ \dag \:  \: More \: Formulas \:  \:  \dag}}}} \\  \\  \\  \footnotesize \bigstar  \:  \bf{Area \: _{Square} = Side \times Side}  \\  \\  \\   \footnotesize\bigstar  \:  \bf{Area \: _{Rectangle} = Lenght \times Breadth} \\  \\  \\  \footnotesize \bigstar \:  \bf{Area \: _{Triangle} =  \frac{1}{2} \times Base \times Height } \\  \\  \\  \footnotesize \bigstar \:  \bf{Area \: _{Parallelogram} = Base \times Height} \\  \\  \\  \footnotesize \bigstar \:  \bf{Area \: _{Trapezium} =  \frac{1}{2} \times [ \: A + B \: ] \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf {Area \: _{Rhombus} = \frac{1}{2} \times Diagonal \: 1 \times Diagonal \: 2}\end{array}}\end{gathered}\end{gathered}

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