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elixir [45]
3 years ago
15

A skydiver free falls from a plane 200 feet above the ground. Which of the following equations could represent the height of the

skydiver as a function of time?
1. h(t) = -16t2 + 200t

2. h(t) = t2 + 199

3. h(t) = -16(t - 3) + 200

4. h(t) = -16t2 + 200
Mathematics
2 answers:
jasenka [17]3 years ago
6 0

Answer:

Katie,

Once the skydiver reaches terminal velocity, then he will be falling with constant speed. The distance he falls in time t will then be d = (160 ft/s)·t. And his altitude above the ground (height h) will be his altitude when the parachute opened minus the distance he has fallen so we can write:

h = (3200 ft) - (160 ft/s)·t

As a point of interest, the time it will take him to fall all the way to the ground is t = (3200 ft)/(160 ft/s) = 20 s

Irina18 [472]3 years ago
5 0

Answer:

h(t) = -16t^2 + 200

Step-by-step explanation:

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Answer:

1. (5x - 2) + (2x - 2) + x = 180^{o}

2. m<J = 113^{o}

3. m<K = 44^{o}

4. m<L = 23^{o}

Step-by-step explanation:

Generally, the sum of angles in a triangle = 180^{o}.

So that;

m<J + m<K + m<L = 180^{o}

(5x - 2) + (2x - 2) + x = 180^{o}

5x + 2x + x -2 -2 = 180^{o}

8x - 4 = 180^{o}

8x = 180^{o} + 4

8x = 184

x = \frac{184}{8}

x = 23^{o}

Thus,

m<J = (5x - 2)

       = 5(23) - 2

       = 113^{o}

m<K = (2x -2)

        = 2(23) - 2

        = 44^{o}

m<L = x

       = 23^{o}

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