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2 years ago

14

Andros has an oil fired heating system. In 30 days period he used a full tank of oil at a constant rate per day . At a different

time of the year the amount of oil andros uses per day is 1/3 of the rate used in 30 days period . How many days should a full tank of oil last at this new rate

1 answer:

Alexandra [31]2 years ago

8 0

Answer:

90 days

Step-by-step explanation:

Let the rate per day for the 30 days period be x

Given that the rate drops to 1/3 of the rate used in 30 days period, it means that the new rate

= 1/3 x

If at a rate of x, the full tank runs for 30 days

at a rate of 1/3 x, the full tank would run for

= x/ (1/3 x) * 30 days

= 3 * 30 days

= 90 days

At the new rate, the full tank of oil will last for 90 days

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What is the approximate age of a woman whose normal systolic pressure measures 125 mm Hg?

sashaice [31]

The approximate age of a woman whose normal systolic pressure measures 125 mm Hg is 31

The function is given as:

$P(A) = 0.006A^2 - 0.02A + 120$

When the normal systolic pressure is 125, it means that:

$P(A) = 125$

So, we have:

$125 = 0.006A^2 - 0.02A + 120$

Subtract 125 from both sides of the equation

$0= 0.006A^2 - 0.02A + 120 -125$

$0= 0.006A^2 - 0.02A - 5$

Rewrite the equation as:

$0.006A^2 - 0.02A - 5 = 0$

Using a graphing calculator, we have:

$A = \{30.58, -27.25\}$

But age cannot be negative.

So, we have:

$A = 30.58$

Approximate

$A =31$

Hence, the age of the woman is 31

Read more about quadratic functions at:

brainly.com/question/11441586

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2 years ago

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Please help!! What Find the Error and explain why it is wrong!

Nata [24]

Answer:

First image attached

The error was done in Step E, because student did not multiply $2\cdot x -8$ by the negative sign in numerator. Step E must be $\frac{2\cdot x -5}{(x+4)\cdot (x-4)}$ .

Second image attached

The error was done in Step C, because the student omitted the $2\cdot a \cdot b$ of the algebraic identity $(a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}$ . Step C must be $5\cdot x = x^{2}+4\cdot x + 4$

Step-by-step explanation:

First image attached

The error was done in Step E, because student did not multiply $2\cdot x -8$ by the negative sign in numerator. The real numerator in Step E should be:

$3-(2\cdot x -8)= 3-2\cdot x+8 = 11-2\cdot x$

Hence, Step E must be $\frac{2\cdot x -5}{(x+4)\cdot (x-4)}$ .

Second image attached

The error was done in Step C, because the student omitted the $2\cdot a \cdot b$ of the algebraic identity $(a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}$ . Step C must be $5\cdot x = x^{2}+4\cdot x + 4$

And further steps are described below:

Step D

$x^{2}-x+4 = 0$

Which according to the Quadratic Formula, represents a polynomial with complex roots. That is: ( $a = 1$ , $b = -1$ , $c = 4$ )

$D = b^{2}-4\cdot a\cdot c$

$D = (-1)-4\cdot (1)\cdot (4)$

$D = -17$ (Conjugated complex roots)

Step E

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Step F

$x = 0.5+i\,1.936\,\lor\,x = 0.5-i\,1.936$

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3 years ago

What power of 10 can you multiply 0.02 by to get a product of 20? Explain your answer.

viva [34]

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So, the answer is 3.

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3 years ago

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Can someone help me?

Pani-rosa [81]

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(−6m)+(−40+−1)=7m−2

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−6m−41−7m=7m−2−7m

−13m−41+41=−2+41

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What mistake I guess Keith did make is he subtracted 2 from -39 which equaled to -37 which caused him divide -37 by 13 when it should have been 39 divided by 13 because he should have left 39 alone and not have subtracted 2 from it also it should not have been negative basically what I'm trying to say is that he did his division and subtraction wrong.

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2 years ago

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Suppose you have 18 more quarters than dimes. You have a total of $8.00. How many of each coin do you have? Use the substitution

kramer

Answer:

18 quarters = $4.50

8.00-4.50=3.50

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