Given set S = <span>{A, B, C, D, E, F, G, H}
There are 8 elements in set S and we are to choose 3 letters at random, the number of ways to choose such is x. It is simply similar to choosing 5 letters at random, which is also equal to x. Since order doesn't matter, n! / (n-m)! where n = 8 and m = 3, which is 336 ways. </span>
The correct answer is: " 
" .
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<u>Step-by-step explanation</u>:
Based on the assumption that the "1" repeats infinitely; in the given value:
" 33.61111111 ...." ;
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Note that the "611" ; after the decimal point; this goes to the "thousandths";
place (is "3 (three) digits long.").
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As such; we rewrite the number as:
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" 
" ;
and we multiply BOTH the "numerator" And the "denominator" by: "1000" :
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→ " 
" ;
to get:
→ " 
" ; → which cannot be reduced any further.
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The correct answer is: " " .
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Hope this is helpful to you!
Wishing you the best!
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Step-by-step explanation:
1st digit is 1 number (1)
2nd digit is (3,4,5) so it's 3 numbers
third digit is (6,7,8,9) is it's 4 numbers
last 7 digits is 10 (0,1,2,3,4,5,6,7,8,9)
multiply
1*3*4*10=120
so answer is 120 phone numbers
Answer:
P = 5
Step-by-step explanation:
2/5(10p) - 2/5(15)= 14
20p/5 - 30/5= 14
4p - 6= 14
4p = 20
p=5
Answer:
9/20
Step-by-step explanation:
First you'd do 3/5 x 3/4 because the denominators aren't the same. When you multiply them you get 9/20. That's your answer! If your not satisfied look it up on Google lol.
