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Fofino [41]
2 years ago
8

1. A quadrilateral has vertices (5, 3) (5,-1) (-1,3) and (-1,-1). What special quadrilateral is formed by connecting the midpoin

ts of the sides?
A. rectangle
B. rhombus
C. kite
D. trapezoid

2. What type of quadrilateral is formed by connecting the points (0,9) (3,6) (0,1) and (-3,6)?

A. rhombus
B. trapezoid
C. kite
D. quadrilateral
Mathematics
1 answer:
antiseptic1488 [7]2 years ago
6 0

Answer:

1. Kite,

2. Kite.

Step-by-step explanation:

1. The quadrilateral form will have 2 equal  pairs of adjacent sides which is a kite.

2. Find the slope and length of the sides:-

slopes (9-6)/ 0-3) = -1

(6-1) / (3-0) = 5/3

(6-1) / (-3-0) = -5/3

(9-6)/(3) = 1

Lengths = sqrt(9 + 9) = sqrt18

sqrt(25 + 9) = sqrt34

sqrt (25 + 9) = sqrt34

sqrt (9 + 9) = sqrt18.

This is another kite.

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PilotLPTM [1.2K]
Try this option:
According to property such triangle
1. area=0.5*a*b, where a and b - the sides of angle 90°.
Using this equation: 180=0.5*40*b, ⇒ b=9.
2. c²=a²+b², ⇒c=√(9²+40²)=41 - the third side of the triangle;
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answer: 90 cm.
3 0
2 years ago
Find m angle ABC <br> I really need the answer to this
damaskus [11]
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As <DBE is a right angle, <DBE is on the same straight line as well,meaning that it would be 90° , a right angle as well.

It also mean that the total sum of the angles unknown would be 90°

To find x,we need to set up an equation:
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Hope it helps!
7 0
2 years ago
Read 2 more answers
Given: ∆ABC, m∠C = 90° CB = 8, m∠B = 38º Find the area of a circumscribed circle. Find the area of the inscribed circle.
vitfil [10]

Answer:

Circumscribed circle: Around 80.95

Inscribed circle: Around 3.298

Step-by-step explanation:

Since C is a right angle, when the circle is circumscribed it will be an inscribed angle with a corresponding arc length of 2*90=180 degrees. This means that AB is the diameter of the circle. Since the cosine of an angle in a right triangle is equivalent to the length of the adjacent side divided by the length of the hypotenuse:

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To find the area of the circumscribed circle:

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To find the area of the inscribed circle, you need the length of AC, which you can find with the Pythagorean Theorem:

AC=\sqrt{10.152^2-8^2}\approx 6.25

The area of the triangle is:

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The semiperimeter of the triangle is:

\dfrac{10.152+6.25+8}{2}\approx 24.4

The radius of the circle is therefore \dfrac{25}{24.4}\approx 1.025

The area of the inscribed circle then is \pi\cdot (1.025)^2\approx 3.298.

Hope this helps!

6 0
3 years ago
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adell [148]
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2 years ago
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Answer:

hello there...

you know BODMAS for sure

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