Step-by-step explanation:
Equation 1
Equation 2
1. A quadrilateral has vertices (5, 3) (5,-1) (-1,3) and (-1,-1). What special quadrilateral is formed by connecting the midpoin
1 answer:
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Here 'a' corresponds to 0.
Now there are two possibilities for 'r' & 't'
Case 1.
They are on the same side to the right of 'a'
In that case 'r' corresponds to 5 & 't' corresponds to 7.
The midpoint of 'r' and 't' shall be
Case 2.
Both are on the left of 'a'.
In that case 'r' corresponds to -5 & 't' corresponds to -7
The midpoint shall be
Case 3.
'r' in on the right of 'a' and 't' is on the left of 'a'
So 'r' corresponds to 5 and 't' corresponds to -7
The midpoint shall be
Case 4.
'r' is on the left of 'a' & 't' is on the right of 'a'.
'r' corresponds to -5 & 't' corresponds to 7
The midpoint shall be
The possible coordinates of the midpoints of rt are 6, -6, 1, -1.