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riadik2000 [5.3K]
3 years ago
6

The equation d=0.05v2+1.1v models the distance, d, that it takes are car traveling v miles per hour to come to a complete stop.

If Hannah’s car stopped after travelling 250 feet on a highway with a speed limit of 65 mph, was Hannah speeding? Explain using math whether she was speeding and how you know.
Mathematics
1 answer:
liq [111]3 years ago
5 0

Answer:

  • <u>Hannah was not speeding because her speed was about 61 mph, which is below the speed limit.</u>

Explanation:

Just to correct some typos, this is the complete question:

<em />

<em>The equation d=0.05v² +  1.1v models the distance, d, that it takes a car traveling at a speed of v miles per hour to come to a complete stop. If Hannah’s car stopped after travelling 250 feet on a highway with a speed limit of 65 mph, was Hannah speeding? Explain using math whether she was speeding and how you know.</em>

<em />

<h2>Solution</h2>

<em />

To find whether Hannah was speeding, you must find the velocity that is solution for the equation:

  • 250=0.05v² +  1.1v

<em />

Write it in standard form:

  • 0.05v² +  1.1v - 250 = 0

Use the quadratic formula:

       v=\dfrac{-1.1\pm\sqrt{(1.1)^2-4(0.05)(-250)}}{2(0.05)}

      v=\dfrac{-1.1\pm 7.1561}{0.1}

       v=60.6\text{ or }v=-82.6

The speed can only be positive; thus, it is about 61 miles per hour, which is below the speed limit of 65mph.

In conclusion, she was not speeding.

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