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alukav5142 [94]
3 years ago
10

Last year during November there was a heatwave. The average daily temperature went from 57°F to 76°F. What was the percent incre

ase in the average daily temperature during the heatwave?
Mathematics
1 answer:
lesya692 [45]3 years ago
8 0

Answer:

hhhh

Step-by-step explanation:

hhhhhh

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Latasha explores some passages in a cave. The elevations of the passages are all above - 10 meters. Let y be the elevation of a
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Answer:

Is this pure maths cause I don't know what's going on here

3 0
3 years ago
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Macy's is having an unbelievable sale this holiday season! All shirts are 205 off and all jeans are 25% off. How much would jean
natita [175]

Step-by-step explanation:

100% - 25% off = 75%

Here, 75% of the initial price X, is the sale price of jeans during the season which is $60.

75/100 × X = $60

75X/100 =$60

( cross multiply)

75X=100×60

75X= 6000

X=6000÷75

X= $80

3 0
2 years ago
A restaurant sold 8 times as many salads as they sold steaks. if they sold 4 steaks, how many salads did they sell?
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32. For every one salad it was 8 steaks, so if they sold 4 steaks, just multiply 4 by 8, where 8 represents the number of salads for every steak. The answer would be 32. Correct me if I'm wrong but that my answer.
7 0
3 years ago
mason made 5 quarts of salsa which of the following can be used to find the number of cups of salsa mason made
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Answer:

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8 0
3 years ago
Complete parts (a) and (b) using the probability distribution below.
katen-ka-za [31]
Μ = (0×0.026) + (1×0.072) +(2×0.152) + (3×0.303) + (4×0.215) + (5×0.164) + (6×0.066) 
μ = 0 + 0.072 + 0.304 + 0.909 + 0.86 + 0.82 + 0.396
μ = 3.361 ≈ 3.4

We need the value of ∑X² to work out the variance
∑X² = (0²×0.026) + (1²×0.072) + (2²×0.152) + (3²×0.303) + (4²×0.215) + (5²×0.164) + (6²×0.066)
∑X² = 0+0.072+0.608+2.727+3.44+4.1+2.376
∑X² = 13.323

Variance = ∑X² - μ²
Variance  = 13.323 - (3.4)² = 1.763 ≈ 2

Standard Deviation = √Variance = √1.8 = 1.3416... ≈ 1.4

The correct answer related to the value of mean and standard deviation is the option D
<span>
An employee works an average of 3.4 overtime hours per week with a standard deviation of approximately 1.4 hours.</span>
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