In the 30-60-90 triangle below, side s has a length of__and side q has a
1 answer:
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Answer:
This contradicts the Mean Value Theorem since there exists a c on (1, 7) such that f '(c) = f(7) − f(1) (7 − 1) , but f is not continuous at x = 3
Step-by-step explanation:
The given function is
When we differentiate this function with respect to x, we get;
We want to find all values of c in (1,7) such that f(7) − f(1) = f '(c)(7 − 1)
This implies that;
If this function satisfies the Mean Value Theorem, then f must be continuous on [1,7] and differentiable on (1,7).
But f is not continuous at x=3, hence this hypothesis of the Mean Value Theorem is contradicted.
Correct answer: 1) (f/g)(x)
Solution: f(x)=x^2-6x-27=(x+3)(x-9)
Solution: f(x)=x^2-6x-27=(x+3)(x-9)