Question

Someone please explain

Answer 1

Answer:

D) 6

Step-by-step explanation:

set Q has 16 values which are all even values from 4 to 36

set Z has 11 values that are multiples of 3 from 4 to 36 (6,9,12,15,etc.) however, we have to eliminate the odd ones, leaving the following six:

6, 12, 18, 24, 30, 36

Answer 2

Answer:

D. 6

Step-by-step explanation:

Key skills needed: Set Similarity

1) The easiest way to teach this is by writing out each set, but I will show it to you in 2 ways.

2) The first way is by writing everything out.

Set Q = 4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36

Set Z = 3,6,9,12,15,18,21,24,27,30,33,36

(I only wrote out Set Z to 36 since Set Q ends at 36. Anything greater than 36 won't even be there in Set Q, so no point in writing more.

• The numbers that are common in both sets are --> 6,12,18,24,30,36
• Therefore D would be your answer.

3) The next way is with using a simple pattern.

Set Q contains all even numbers from 4 to 36

Set Z contains all multiples of 3 (no limits)

Therefore, the numbers that are in both sets would be:

The even multiples of 3 that are bigger than 4 and less than 36.

4) Those even multiples of 3 would be  ---> 6,12,18,24,30,36

• That means there are 6 numbers in common.
• That means D is your answer.

Both show that D is the answer, so I would say D as the answer very confidently.

Hope you understood and have a nice day!! :D