Answer:
I think it's A: Similar - AA
Step-by-step explanation:
We know that ∠K≅∠N & ∠L≅∠P, so that gives us 2 sets of congruent angles
Answer:
m<A = 30 degrees.
Step-by-step explanation:
m < C in triangle ABC = m < C in EDC so
x + 13 + 42 + x + 13 = 180
2x = 180 - 13 - 13 - 42
2x = 112
x = 56.
So m < C = 56+13 = 69.
m < B = m < D = 81
M < A = 180 - 69 - 81
= 180 - 150 = 30.
Answer:
Step-by-step explanation:
-3X-3<6
-3X<9
X>-3 (NOTICE THE SIGN CHANGE BECAUSE WE DIVIDED BY A NEGATIVE NUMBER)
(-3,00) INTERVAL NOTATION
Write the left side of the given expression as N/D, where
N = sinA - sin3A + sin5A - sin7A
D = cosA - cos3A - cos5A + cos7A
Therefore we want to show that N/D = cot2A.
We shall use these identities:
sin x - sin y = 2cos((x+y)/2)*sin((x-y)/2)
cos x - cos y = -2sin((x+y)/2)*sin((x-y)2)
N = -(sin7A - sinA) + sin5A - sin3A
= -2cos4A*sin3A + 2cos4A*sinA
= 2cos4A(sinA - sin3A)
= 2cos4A*2cos(2A)sin(-A)
= -4cos4A*cos2A*sinA
D = cos7A + cosA - (cos5A + cos3A)
= 2cos4A*cos3A - 2cos4A*cosA
= 2cos4A(cos3A - cosA)
= 2cos4A*(-2)sin2A*sinA
= -4cos4A*sin2A*sinA
Therefore
N/D = [-4cos4A*cos2A*sinA]/[-4cos4A*sin2A*sinA]
= cos2A/sin2A
= cot2A
This verifies the identity.
<span>No.
The test is not a fair test. The test is artificial. Testing the disinfectant against bacteria in a
test tube is not representative of the effectiveness of the disinfectant
against microbes in the environment. Test tube tests test for efficacy.
Effectiveness can only be tested out in the environment.</span>
