Ask question

Ask question

All categories

3 years ago

15

To make green paint, students mixed yellow paint with blue paint. The table below shows how many yellow and blue drops from a dr

opper several students used to make shades of green paint

1 answer:

stellarik [79]3 years ago

3 0

Answer:

there is no pictures. so there for i can not answer your question

You might be interested in

Need help ASAP if any can help me that’ll mean a lot I’ll heart your answer :)

Dominik [7]

Answer:

13p+11.75 is no more than 480

Step-by-step explanation:

plz give me brainliest if possible

4 0

3 years ago

A baker has 6 small bags of flour. Each bag weighs 1 pound. She divides each bag into thirds. How many 1/3 - pound bags of flour

lana [24]

Answer:

18 smaller bags

Step-by-step explanation:

Each one pound bag becomes 3 one-third pound bags.

So 6 one pound bags will become 6×3=18 one-third pound bags.

5 0

4 years ago

Can someone please please help me

Alekssandra [29.7K]

Answer:

The answer is None

Step-by-step explanation:

Multiply 6 2 and 1 and also multiply 12 4 and 2 separately now divide 96 with 12 and you get 8 which is none of the answer choices

6 0

3 years ago

Read 2 more answers

Which series of transformations will not map figure H onto itself

7nadin3 [17]

Answer:

D

Step-by-step explanation:

Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).

Consider option A.

1st transformation $(x+0,y-2)$ will map vertices of the square into points

$(2,1)\rightarrow (2,-1);$
$(1,2)\rightarrow (1,0);$
$(2,3)\rightarrow (2,1);$
$(3,2)\rightarrow (3,0).$

2nd transformation = reflection over y = 1 has the rule (x,2-y). So,

$(2,-1)\rightarrow (2,3);$
$(1,0)\rightarrow (1,2);$
$(2,1)\rightarrow (2,1);$
$(3,0)\rightarrow (3,2)$

These points are exactly the vertices of the initial square.

Consider option B.

1st transformation $(x+2,y-0)$ will map vertices of the square into points

$(2,1)\rightarrow (4,1);$
$(1,2)\rightarrow (3,2);$
$(2,3)\rightarrow (4,3);$
$(3,2)\rightarrow (5,2).$

2nd transformation = reflection over x = 3 has the rule (6-x,y). So,

$(4,1)\rightarrow (2,1);$
$(3,2)\rightarrow (3,2);$
$(4,3)\rightarrow (2,3);$
$(5,2)\rightarrow (1,2)$

These points are exactly the vertices of the initial square.

Consider option C.

1st transformation $(x+3,y+3)$ will map vertices of the square into points

$(2,1)\rightarrow (5,4);$
$(1,2)\rightarrow (4,5);$
$(2,3)\rightarrow (5,6);$
$(3,2)\rightarrow (6,5).$

2nd transformation = reflection over y = -x + 7 will map vertices into points

$(5,4)\rightarrow (3,2);$
$(4,5)\rightarrow (2,3);$
$(5,6)\rightarrow (1,2);$
$(6,5)\rightarrow (2,1)$

These points are exactly the vertices of the initial square.

Consider option D.

1st transformation $(x-3,y-3)$ will map vertices of the square into points

$(2,1)\rightarrow (-1,-2);$
$(1,2)\rightarrow (-2,-1);$
$(2,3)\rightarrow (-1,0);$
$(3,2)\rightarrow (0,-1).$

2nd transformation = reflection over y = -x + 2 will map vertices into points

$(-1,-2)\rightarrow (4,3);$
$(-2,-1)\rightarrow (3,4);$
$(-1,0)\rightarrow (2,3);$
$(0,-1)\rightarrow (3,2)$

These points are not the vertices of the initial square.

5 0

3 years ago

Pay the bill using the fewest possible bills/coins

marysya [2.9K]

Answers:

Open the pdf below and youll find what you need. also do the largest bills you can.

4 0

3 years ago