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avanturin [10]
3 years ago
15

To make green paint, students mixed yellow paint with blue paint. The table below shows how many yellow and blue drops from a dr

opper several students used to make shades of green paint
Mathematics
1 answer:
stellarik [79]3 years ago
3 0

Answer:

there is no pictures. so there for i can not answer your question

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I am supposed to model this question with a inequality equation. Could someone please show me how I would write the equation?
lesya [120]
Scavdfdscdeereedefrrdeeeeeqwwwwwwwwwwwrrtrrrrrresfr
4 0
3 years ago
P(a) = 2a -3; find p(a) = 15
Andrei [34K]
Since both is equal to p(a), you can set them as equal to each other:

15 = 2a - 3
18 = 2a
9 = a
8 0
3 years ago
Which set of rational number is correct ordered from least to greatest
MrMuchimi
B is correct answer
3 0
3 years ago
tom and lisa each had a birthday party at hurricane harbor last weekend . the cost of admission was $137.50 for 13 children and
gregori [183]

Answer:

Per child admission costs $8.5

Per Adult admission costs $13.5

Step-by-step explanation:

Let x be the amount of admission per child and y be the amount of admission per adult

For Tom's party:

13x+2y=137.50      (Equation 1)

For Lisa's Party:

9x+2y=105.50       (Equation 2)

Using Elimination Method:

Add Equation 1 & 2

13x+2y=137.50

9x+2y=105.50  

-    -   = -         (Change of Signs)

---------------------------------

4x+0y=34.00      

x=34/4

x=8.5

Putting the value of x in Equation 2

13(8.5)+2y=137.50

110.5+2y=137.50

2y=137.50-110.50

2y=27

y=27/2

y=13.5

4 0
2 years ago
find the slope of the curve y=x^2-2x-5 at the point P(2,5) by finding the limit of secant slopes through point P
Fynjy0 [20]

The point (2, 5) is not on the curve; probably you meant to say (2, -5)?

Consider an arbitrary point Q on the curve to the right of P, (t,y(t))=(t,t^2-2t-5), where t>2. The slope of the secant line through P and Q is given by the difference quotient,

\dfrac{(t^2-2t-5)-(-5)}{t-2}=\dfrac{t^2-2t}{t-2}=\dfrac{t(t-2)}{t-2}=t

where we are allowed to simplify because t\neq2.

Then the equation of the secant line is

y-(-5)=t(x-2)\implies y=t(x-2)-5

Taking the limit as t\to2, we have

\displaystyle\lim_{t\to2}t(x-2)-5=2(x-2)-5=2x-9

so the slope of the line tangent to the curve at P as slope 2.

- - -

We can verify this with differentiation. Taking the derivative, we get

\dfrac{\mathrm dy}{\mathrm dx}=2x-2

and at x=2, we get a slope of 2(2)-2=2, as expected.

4 0
3 years ago
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