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3 years ago

I am supposed to model this question with a inequality equation. Could someone please show me how I would write the equation?

Mathematics

1 answer:

lesya [120]3 years ago

4 0

Scavdfdscdeereedefrrdeeeeeqwwwwwwwwwwwrrtrrrrrresfr

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Which of these expressions shows a correct way to set up the slope formula for the line that passes through the points (5, 0) an

vaieri [72.5K]

Answer:

Step-by-step explanation:

its c because if we input the numbers into the slope formula y2 - y1 over x2 - x1 it equals -6 - 0 over 6 - 5

3 0

3 years ago

What is m∠CAD?

SSSSS [86.1K]

Answer:

100

Step-by-step explanation:

All angles in a triangle equal to 180.

80+20=100

180-100=80

The line is 180

180-80=100

8 0

3 years ago

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dimaraw [331]

Answer:

$-7 < -4 < 0 < 7$

Step-by-step explanation:

Given

Change: -4, 7, -7 and 0

Required

Compare them

From the list of given options, we can observe that the inequality < is used in all options.

This implies that we arrange from least to highest

The least is -7

Then, -4

Then 0

And lastly, 7

So, we have:

$-7 < -4 < 0 < 7$

3 0

3 years ago

Find (f • g) when f(x) = x^2 + 5x + 6 and g(x) = 1/x+3

Nikitich [7]

Answer:

option D

Step-by-step explanation:

$f(x) = x^2 + 5x + 6$

$g(x)= \frac{1}{x+3}$

(fog)(x) = f(g(x))

Plug in g(x) in f(x)

We plug in 1/x+3 in the place of x in f(x)

$f(g(x))= f(\frac{1}{x+3})= (\frac{1}{x+3})^2 + 5(\frac{1}{x+3}) + 6$

To simplify it we take LCD

LCD is (x+3)(x+3)

$\frac{1}{(x+3)(x+3)}+5\frac{1*(x+3)}{(x+3)(x+3)}+\frac{6(x+3)(x+3)}{(x+3)(x+3)}$

$\frac{1}{x^2+6x+9}+\frac{(5x+15)}{x^2+6x+9}+\frac{6x^2+36x+54}{x^2+6x+9}$

All the denominators are same so we combine the numerators

$\frac{1+5x+15+6x^2+36x+54}{x^2+6x+9}$

$\frac{6x^2+41x+70}{x^2+6x+9}$

Option D is correct

8 0

3 years ago

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1.3485 divided by 0.31 please

levacccp [35]

The Answer Is 4.35. Hope This Helps.

6 0

3 years ago

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