Question

Particle x moves along the positive x-axis so that it's position at time t is less than equal to 0 is given by x(t)= 5t^3 - 9t^2 + 7. Is particle x moving toward the right at time t=1?

Answer 1

Answer:

YES

Step-by-step explanation:

Given the position of the particle expressed using the expression;

x(t)= 5t^3 - 9t^2 + 7 where;

x moves along the positive x-axis

when t = 1

x(1) = 5(1)^3 - 9(1)^2 + 7

x(1) = 5 - 9 + 7

x(1) = -4 + 7

x(1) = 3

Since the position of the particle is positive at t = 1, hence the particle is moving towards the right at time t = 1