use sin^2(x) =1/2 * (1-cos2x)
cos 2x - use def cosx from table
f(x)=sin^2(0)
f'(x)=2*sin(x)*cos(x)
therefore f'(x)=sin(2x)
f''(x)=2cos(2x)
f'''(x)=-4sin(2x)=-4*f'(x)
<span>putting it into maclaurin's series</span>
<span>We get,</span>
<span> 0+0+ 2x^2/2! + 0...</span>
Dwight's salary after t year is represented by
<h3><u><em>Solution:</em></u></h3>
Given that
Dwight has a new job that guarantees a six percent raise for each year with the company.
His initial salary is $52,000 per year.
Need to determine equation which models Dwight's salary after t years
Dwight's initial salary = $52,000 per year.
As job guarantees a six percent raise for each year
Dwight's salary after 1 year = 52000 + 6% of 52000 = 52000 + 0.06 x 52000 = 52000 (1.06)
Dwight's salary after 2 year = (52000 x 1.06) + 6 % of (52000 x 1.06)
Hence Dwight's salary after t year is represented by =
Answer:
x≥4
Step-by-step explanation:
We want to solve for x in
Let us add 3 to both sides:
We simplify to get:
Divide through by 2 to get:
I think it’s x=10? because if that is equal to 110 then 110-30=80 | 8x/80 x=10