Ask question

Ask question

All categories

Paladinen [302]

3 years ago

7

Est form. Lessons 3-5) 2 9

1 answer:

Gekata [30.6K]3 years ago

3 0

Answer:

what is this mean is there a question

You might be interested in

If it takes B hours to walk a certain distance at the rate of 3 miles per hour, the number of hours it takes to return the same

natita [175]

Answer:

It will take 0.75B hours for the return leg

Step-by-step explanation:

Here, given that the first leg of the trip was for B hours at 3 miles per hour , we want to calculate the number of hours the return leg will take at 4 miles per hour given that it is the same distance.

Mathematically, we know that ;

Distance = speed * time

So the distance taken on the first leg of the trip would be;

Distance = 3 miles per hour * B hours = 3B miles

Now, this distance was traveled on the return leg also.

This means that the time taken here will be;

Time on return leg = distance/speed = 3B/4 = 0.75B hours

5 0

3 years ago

Choose the product. -7 p3 (4 p2 + 3 p - 1)

sashaice [31]

Answer:

The product is -28p5-3p4+7p4

Step-by-step explanation:

In this case we will use -7p3 to multiply all the figures in the bracket

Which means -28p5-3p4+7p3

Always remember that -×-=+ , +×+=+ ,-×+=-...

Thanks

7 0

3 years ago

2. In how many ways can 3 different novels, 2 different mathematics books and 5 different chemistry books be arranged on a books

insens350 [35]

The number of ways of the books can be arranged are illustrations of permutations.

When the books are arranged in any order, the number of arrangements is 3628800
When the mathematics book must not be together, the number of arrangements is 2903040
When the novels must be together, and the chemistry books must be together, the number of arrangements is 17280
When the mathematics books must be together, and the novels must not be together, the number of arrangements is 302400

The given parameters are:

$\mathbf{Novels = 3}$

$\mathbf{Mathematics = 2}$

$\mathbf{Chemistry = 5}$

<u />

<u>(a) The books in any order</u>

First, we calculate the total number of books

$\mathbf{n = Novels + Mathematics + Chemistry}$

$\mathbf{n = 3 + 2 + 5}$

$\mathbf{n = 10}$

The number of arrangement is n!:

So, we have:

$\mathbf{n! = 10!}$

$\mathbf{n! = 3628800}$

<u>(b) The mathematics book, not together</u>

There are 2 mathematics books.

If the mathematics books, must be together

The number of arrangements is:

$\mathbf{Maths\ together = 2 \times 9!}$

Using the complement rule, we have:

$\mathbf{Maths\ not\ together = Total - Maths\ together}$

This gives

$\mathbf{Maths\ not\ together = 3628800 - 2 \times 9!}$

$\mathbf{Maths\ not\ together = 2903040}$

<u>(c) The novels must be together and the chemistry books, together</u>

We have:

$\mathbf{Novels = 3}$

$\mathbf{Chemistry = 5}$

First, arrange the novels in:

$\mathbf{Novels = 3!\ ways}$

Next, arrange the chemistry books in:

$\mathbf{Chemistry = 5!\ ways}$

Now, the 5 chemistry books will be taken as 1; the novels will also be taken as 1.

Literally, the number of books now is:

$\mathbf{n =Mathematics + 1 + 1}$

$\mathbf{n =2 + 1 + 1}$

$\mathbf{n =4}$

So, the number of arrangements is:

$\mathbf{Arrangements = n! \times 3! \times 5!}$

$\mathbf{Arrangements = 4! \times 3! \times 5!}$

$\mathbf{Arrangements = 17280}$

<u>(d) The mathematics must be together and the chemistry books, not together</u>

We have:

$\mathbf{Mathematics = 2}$

$\mathbf{Novels = 3}$

$\mathbf{Chemistry = 5}$

First, arrange the mathematics in:

$\mathbf{Mathematics = 2!}$

Literally, the number of chemistry and mathematics now is:

$\mathbf{n =Chemistry + 1}$

$\mathbf{n =5 + 1}$

$\mathbf{n =6}$

So, the number of arrangements of these books is:

$\mathbf{Arrangements = n! \times 2!}$

$\mathbf{Arrangements = 6! \times 2!}$

Now, there are 7 spaces between the chemistry and mathematics books.

For the 3 novels not to be together, the number of arrangement is:

$\mathbf{Arrangements = ^7P_3}$

So, the total arrangement is:

$\mathbf{Total = 6! \times 2!\times ^7P_3}$

$\mathbf{Total = 6! \times 2!\times 210}$

$\mathbf{Total = 302400}$

Read more about permutations at:

brainly.com/question/1216161

8 0

3 years ago

You downloaded a video game to your computer. Let l represent the number of levels played. Write an inequality to determine the

Phantasy [73]

If it takes m minutes to play on level, then in 60 minutes, the maximum number of levels you can play is 60 / m. Then, l <= 60/m.

8 0

3 years ago

The measure of three angles of a quadrilateral are 80 90 and 103 degrees. find the measure of the fourth angle

Ronch [10]

In a quadrilateral the angles should add up to 360 degrees.
360-80-90-103= 87

So 87 degrees

6 0

4 years ago