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Paladinen [302]
3 years ago
7

Est form. Lessons 3-5) 2 9

Mathematics
1 answer:
Gekata [30.6K]3 years ago
3 0

Answer:

what is this mean is there a question

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Jon and Anne had an equal amount of money. Jon spent $10. Anne spent $30. Now Jon has twice as much money as Anne. How much did
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They would have had $50 at the beginning
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Abby's friend told her that he drew a quadrilateral with exactly one pair of parallel sides. Abby said it must be a trapezoid. I
Ratling [72]

Answer:

Yes, she is correct

Step-by-step explanation:

A trapezoid has exactly one pair of parallel lines and 4 sides

8 0
2 years ago
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What are the types of roots of the equation below?<br> - 81=0
Tju [1.3M]

Option B, that is Two Complex and Two Real which are x + 3, x - 3, x + 3i and x - 3i, are the types of roots of the equation x⁴ - 81 = 0. This can be obtained by finding root of the equation using algebraic identity.    

<h3>What are the types of roots of the equation below?</h3>

Here in the question it is given that,

  • the equation x⁴ - 81 = 0

By using algebraic identity, (a + b)(a - b) = a² - b², we get,  

⇒ x⁴ - 81 = 0                      

⇒ (x² +  9)(x² - 9) = 0

⇒ (x² + 9)(x² - 9) = 0

  1. (x² -  9) = (x² - 3²) = (x - 3)(x + 3) [using algebraic identity, (a + b)(a - b) = a² - b²]
  2. x² + 9 = 0 ⇒ x² = -9 ⇒ x = √-9 ⇒ x= √-1√9 ⇒x = ± 3i

⇒ (x² + 9) = (x - 3i)(x + 3i)

Now the equation becomes,

[(x - 3)(x + 3)][(x - 3i)(x + 3i)] = 0

Therefore x + 3, x - 3, x + 3i and x - 3i are the roots of the equation

To check whether the roots are correct multiply the roots with each other,

⇒ [(x - 3)(x + 3)][(x - 3i)(x + 3i)] = 0

⇒ [x² - 3x + 3x - 9][x² - 3xi + 3xi - 9i²] = 0

⇒ (x² +0x - 9)(x² +0xi - 9(- 1)) = 0

⇒ (x² - 9)(x² + 9) = 0

⇒ x⁴ - 9x² + 9x² - 81 = 0

⇒ x⁴ - 81 = 0

Hence Option B, that is Two Complex and Two Real which are x + 3, x - 3, x + 3i and x - 3i, are the types of roots of the equation x⁴ - 81 = 0.

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: What are the types of roots of the equation below?

x⁴ - 81 = 0

A) Four Complex

B) Two Complex and Two Real

C) Four Real

Learn more about roots of equation here:

brainly.com/question/26926523

#SPJ9

5 0
1 year ago
Which is equivalent to sqrt x^10<br> A. X-5<br> B. X -1/5<br> C. X sqrt 10<br> D. X 1/5<br> E. X^5
Lesechka [4]
<h3>Answer:  E) x^5</h3>

\sqrt{x^{10}} = x^5

=====================================================

Explanation:

We simply take half of the exponent 10 to get 5. This applies to square roots only.

So the rule is \sqrt{a^b} = a^{b/2}

A more general rule is

\sqrt[n]{a^b} = a^{b/n}

If n = 2, then we're dealing with square roots like with this problem. In this case, a = x and b = 10.

5 0
2 years ago
Read 2 more answers
Anybody know the answer?
xxTIMURxx [149]
The slope is 3
do you need the steps?
6 0
2 years ago
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