Answer:
Henry's balloon was farther from the town at the beginning and Henry's balloon traveled more quickly.
Step-by-step explanation:
The distance of Tasha's balloon from the town is represented by the function y = 8x+ 20 ............. (1)
Where y is the distance in miles from the town and x represents the time of fly in hours.
So, at the start of the journey i.e. at x = 0, y = 20 miles {From equation (1)} from the town.
Again, Tasha's balloon is traveling at a rate of 8 miles per hour.
Now, Henry's balloon begins 30 miles from the town and is 48 miles from the town after 2 hours.
So, Henry's balloon traveling with the speed of
miles per hour.
Therefore, Henry's balloon was farther from the town at the beginning i.e. 30 miles from the town. And Henry's balloon traveled more quickly i.e at the rate of 9 miles per hour. (Answer)
Answer:
The bearing needed to navigate from island B to island C is approximately 38.213º.
Step-by-step explanation:
The geometrical diagram representing the statement is introduced below as attachment, and from Trigonometry we determine that bearing needed to navigate from island B to C by the Cosine Law:
(1)
Where:
- The distance from A to C, measured in miles.
- The distance from A to B, measured in miles.
- The distance from B to C, measured in miles.
- Bearing from island B to island C, measured in sexagesimal degrees.
Then, we clear the bearing angle within the equation:


(2)
If we know that
,
,
, then the bearing from island B to island C:
![\theta = \cos^{-1}\left[\frac{(7\mi)^{2}+(8\,mi)^{2}-(5\,mi)^{2}}{2\cdot (8\,mi)\cdot (7\,mi)} \right]](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%5Ccos%5E%7B-1%7D%5Cleft%5B%5Cfrac%7B%287%5Cmi%29%5E%7B2%7D%2B%288%5C%2Cmi%29%5E%7B2%7D-%285%5C%2Cmi%29%5E%7B2%7D%7D%7B2%5Ccdot%20%288%5C%2Cmi%29%5Ccdot%20%287%5C%2Cmi%29%7D%20%5Cright%5D)

The bearing needed to navigate from island B to island C is approximately 38.213º.
Answer:
1. x< 3
2. x>12
have a great day :)
Step-by-step explanation: