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4 years ago

Give a real-world example of an

Mathematics

2 answers:

Tamiku [17]4 years ago

6 0

Ok so there is a a die with the numbers
1,2,2,3,3,3
rolling a 1 is 1/6
rolling a 2 is 2/6=1/3
rolling a 3 is 3/6=1/2

Solnce55 [7]4 years ago

6 0

A weighted die where each face's value is directly proportional to its probability.

Therefore, 1 would have a 1/21 chance, 2 would have 2/21 and so on.

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3 years ago

Larry is trying to predict how long it will take him to read a 500–page book. If he knows that he can read 50 pages an hour, wha

mihalych1998 [28]

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3 years ago

Of the 42 people who work at white side industries, 5/6 work in the manufacturing plant. How many people work in the manufacturi

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3 years ago

I would like to purchase 20 products at a cost 65.00 per product. what will be my total? your state has 3.5% sales tax

xxTIMURxx [149]

20*65 = 1300
That's the price without tax.
Now to find tax:
1300*.035 = 45.5
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5 0

3 years ago

Read 2 more answers

A baseball coach is creating a nine-player batting order by selecting from a team of 15 players. How many different batting orde

zzz [600]

Answer:

1,816,214,400 batting orders are possible.

Step-by-step explanation:

The order is important.

Suppose we had a two player batting order.

A batting order of Jonathan Schoop and Manny Machado is a different order than Manny Machado and Jonathan Schoop. So we use the permutations formula.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

$P_{(n,x)} = \frac{n!}{(n-x)!)}$

A baseball coach is creating a nine-player batting order by selecting from a team of 15 players. How many different batting orders are possible?

Selection of 9 players from a set of 15 players. So

$P_{15,9} = \frac{15!}{(15-9)!} = \frac{15!}{6!} = 1816214400$

1,816,214,400 batting orders are possible.

4 0

3 years ago