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3 years ago

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Pleaseeee helpp it’s due in 9 minutes helpp

1 answer:

defon3 years ago

4 0

C. $30.00 is the answer !!!!!!

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Trapezoids and kites

lisov135 [29]

QUESTION 3

The sum of the interior angles of a kite is $360\degree$ .

$\Rightarrow 36\degree +70\degree+m$ .

$\Rightarrow 106\degree+m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

But the two remaining opposite angles of the kite are congruent.

$\Rightarrow m$

$\Rightarrow m$ .

$\Rightarrow 2m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

QUESTION 4

RH is the hypotenuse of the right triangle formed by the triangle with side lengths, RH,12, and 20.

Using the Pythagoras Theorem, we obtain;

$|RH|^2=12^2+20^2$

$|RH|^2=144+400$

$|RH|^2=544$

$|RH|=\sqrt{544}$

$|RH|=4\sqrt{34}$

QUESTION 5

The given figure is an isosceles trapezium.

The base angles of an isosceles trapezium are equal.

Therefore $m$

QUESTION 6

The measure of angle Y and Z are supplementary angles.

The two angles form a pair of co-interior angles of the trapezium.

This implies that;

$m$

$\Rightarrow m$

$\Rightarrow m$

QUESTION 7

The sum of the interior angles of a kite is $360\degree$ .

$\Rightarrow 48\degree +110\degree+m$ .

$\Rightarrow 158\degree+m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

But the two remaining opposite angles are congruent.

$\Rightarrow m$

$\Rightarrow m$ .

$\Rightarrow 2m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

QUESTION 8

The diagonals of the kite meet at right angles.

The length of BC can also be found using Pythagoras Theorem;

$|BC|^2=4^2+7^2$

$\Rightarrow |BC|^2=16+49$

$\Rightarrow |BC|^2=65$

$\Rightarrow |BC|=\sqrt{65}$

QUESTION 9.

The sum of the interior angles of a trapezium is $360\degree$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

But the measure of angle M and K are congruent.

$\Rightarrow m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

$\Rightarrow m$ .

6 0

3 years ago

If x^2 = 16(5), then x =

Bogdan [553]

Answer:

$4\sqrt{5}$ or 8.944

Step-by-step explanation:

$x^{2} = 16(5)$

Simplify

$x^{2} =80$

Square root both sides to get x by itself

$\sqrt{x^{2} } =\sqrt{80}$

$4\sqrt{5}$ or 8.944

6 0

3 years ago

150 thousand times 7

Arada [10]

The equation 150 thousand times 7 equals 1,050,000.

150,000*7= 1050000

8 0

3 years ago

What are the solutions of the quadratic equation?

Oliga [24]

Answer:

d)X=4 or x=-2

Step-by-step explanation:

X²-2x=8

X²-2x-8=0

(x-4)(x+2)=0

X-4=0 or x+2=0

X=4 or x=-2

4 0

2 years ago

Read 2 more answers

What 21 over 4 equivalent to

Law Incorporation [45]

21/4 is equivalent to...

4 x 5 = 20
so, 21/4 = 5 1/4

5 1/4 = 5.25

5 1/4 = 5 2/8 = 42/8

42/8 = 84/16

4 0

3 years ago

Read 2 more answers