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Sunny_sXe [5.5K]
3 years ago
13

Find angle 1, if angle 2 = 56 and m LJKL = 145

Mathematics
1 answer:
Alexandra [31]3 years ago
3 0

Answer: NEED PICTURE TO ANSWER, we dont know if it a square or if its a rectangle, sry

Step-by-step explanation:

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balandron [24]

Answer:

16

notice how a right triangle was formed, and the Pythagorean theorem could be used to solve this :

a^2 + b^2 = c^2

a^2 + 15^2 = 17^2

a^2 + 225 = 289

a^2 = 64

a= 8

multiply it by 2 to get the side of the base

8 * 2 = 16

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3 years ago
Tyler wants to buy a new television that costs $312. He has already saved $96. He plans to save $24 per week over the next few w
Elena L [17]

Answer:

a

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
The graph below shows two polynomial functions, f(x) and g(x): Graph of f of x equals x squared minus 2 x plus 1. Graph of g of
IceJOKER [234]

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Answer:

  (c)  f(x) is an even degree polynomial with a positive leading coefficient.

Step-by-step explanation:

The leading terms of the two functions are ...

  f(x): x² (even degree, positive coefficient: 1)

  g(x): x³ (odd degree, positive coefficient: 1)

Then it is true that ...

  f(x) is an even degree polynomial with a positive leading coefficient

8 0
3 years ago
While driving to the school, I was 20 miles from the school at 7:00. By 7:15, I was 8 miles away from the school. What was my ra
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Answer:

your rate of change was 40%

Step-by-step explanation:

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E%7B2%7D-5x%2B6%7D%7B2x%5E%7B2%7D-7x%2B6%20%7D" id="TexFormula1" title="\frac{x^{
il63 [147K]

Answer:

\frac{x-3}{2x-3}. hole or removable discontinuity at x=2

Step-by-step explanation:

Well generally if you want the simplest form, you factor each the denominator and numerator and then see if you can cancel any of the factors out (because they're in the denominator and numerator)

So let's start by factoring the first equation:

x^2-5x+6

Now let's find what ac is (it's just c since a=1...)

AC= 6

List factors of -6

\pm1, \pm2, \pm3, \pm6.

Now we have to look for two numbers that add up to -5. It's a bit obvious here since there isn't many factors, but it's -2 and -3, and they're both negative since 6 is positive, and -5 is negative...

So using these two factors we get

(x-2)(x-3)

Ok now let's factor the second equation:

2x^2-7x+6

Multiply a and c

AC = 12

List factors of 12:

\pm1, \pm2, \pm3, \pm4, \pm6, \pm12.

Factors that add up to -7 and multiply to 12:

-3\ and\ -4

Rewrite equation:

2x^2-4x-3x+6

Group terms:

(2x^2-4x)+(-3x+6)

Factor out GCF:

2x(x-2)-3(x-2)

Rewrite:

(2x-3)(x-2)

Now let's write out the equation using these factors:

\frac{(x-2)(x-3)}{(2x-3)(x-2)}.

Here we can factor out the x-2 and the simplified form is:

\frac{x-3}{2x-3}

So we can "technically" define f(2) using the most simplified form, but it's removable discontinuity, so it has a hole as x=2. since it makes (x-2) equal to 0 (2-2) = 0.

8 0
2 years ago
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