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Gnesinka [82]
2 years ago
11

Tiffany is sending a package that may not exceed 16 pounds. the package contains books that weigh a total of 9 3/8 pounds. the o

ther items to be sent weigh 3/5 the weight of the books. Will Tiffany be able to send the package?
Mathematics
1 answer:
babunello [35]2 years ago
5 0
Yes Tiffany will be able to
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Please help i dont undertand it
n200080 [17]
B
AKA 2

I have Khan Acadamy!!

Your welcome!
5 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%7Ba%20%7D%5E%7B2%7D%20%20%2B%208a%20%2B%2015%20%3D%200" id="TexFormula1" title=" {a }^{2}
NISA [10]

Answer:

a = - 5, a = - 3

Step-by-step explanation:

Given

a² + 8a + 15 = 0 ← in standard form

(a + 3)(a + 5) = 0 ← in factored form

Equate each factor to zero and solve for a

a + 3 = 0 ⇒ a = - 3

a + 5 = 0 ⇒ a = - 5

8 0
3 years ago
Suppose a city with population 900,000 has been growing at a rate of ​8% per year. If this rate​ continues, find the population
shepuryov [24]

Answer:

4892886.37133

Step-by-step explanation:

4 0
2 years ago
The time that it takes a randomly selected job applicant to perform a certain task has a distribution that can be approximated b
storchak [24]

Answer:

A task time of 177.125s qualify individuals for such training.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

A distribution that can be approximated by a normal distribution with a mean value of 145 sec and a standard deviation of 25 sec, so \mu = 145, \sigma = 25.

The fastest 10% are to be given advanced training. What task times qualify individuals for such training?

This is the value of X when Z has a pvalue of 0.90.

Z has a pvalue of 0.90 when it is between 1.28 and 1.29. So we want to find X when Z = 1.285.

So

Z = \frac{X - \mu}{\sigma}

1.285 = \frac{X - 145}{25}

X - 145 = 32.125

X = 177.125

A task time of 177.125s qualify individuals for such training.

7 0
3 years ago
What is 1/5 divided by 5/7
vampirchik [111]
1/5 divided by 5/7 is 7/25
1/5 ÷ 7/5 = 7/25

Your answer is 7/25


5 0
3 years ago
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