If f(x) = 3x5 + 4x3 + 3, then what is the remainder when f(x) is divided by<br> x

Irina-Kira [14]

Should be 11 if i did it correctly <span />

6 0

3 years ago

Given the following: P(A) =0.3 P(B) = 0.2 P(A OR B) = 0.5 P(A AND B) = 0 Which of the following is true?a. A and B are disjoint.

erastova [34]

Answer:

a. A and B are disjoint

Step-by-step explanation:

We know that P(A and B)=0, It means that event A and event B have nothing in common and it means that event A and event B are disjoints events.

The event A and event B are independent if

P( A and B)= P(A)*P(B)

P(A)*P(B)=0.3*0.2=0.06

So, P(A and B)≠P(A)*P(B)

Hence events A and B are not independent.

Option a is A and B are disjoints which is correct

Option b is A and B are neither disjoints nor independent which is partially false as A and B are disjoints event.

Option c states that A and B are independent which is clearly false.

Option d states that A and B are disjoints and independent which is partially false as A and B are not independent.

Hence the correct option is option A.

5 0

3 years ago

Solve each inequality, and then drag the correct solution graph to the inequality.

Nesterboy [21]

The correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

(NOTE: The graphs are labelled A, B and C from left to right)

For the first inequality,

$4(9x-18)>3(8x+12)$

First, clear the brackets,

$36x-72>24x+36$

Then, collect like terms

$36x-24x>36+72\\12x >108$

Now divide both sides by 12

$\frac{12x}{12} > \frac{108}{12}$

∴ $x > 9$

For the second inequality

$-\frac{1}{3}(12x+6) \geq -2x +14$

First, clear the fraction by multiplying both sides by 3

$3 \times[-\frac{1}{3}(12x+6)] \geq3 \times( -2x +14)$

$-1(12x+6) \geq -6x +42$

Now, open the bracket

$-12x-6 \geq -6x +42$

Collect like terms

$-6 -42\geq -6x +12x$

$-48\geq 6x$

Divide both sides by 6

$\frac{-48}{6} \geq \frac{6x}{6}$

$-8\geq x$

∴ $x\leq -8$

For the third inequality,

$1.6(x+8)\geq 38.4$

First, clear the brackets

$1.6x + 12.8\geq 38.4$

Collect likes terms

$1.6x \geq 38.4-12.8$

$1.6x \geq 25.6$

Divide both sides by 1.6

$\frac{1.6x}{1.6}\geq \frac{25.6}{1.6}$

∴ $x \geq 16$

Let the graphs be A, B and C from left to right

The first graph (A) shows $x\leq -8$ and this matches the 2nd inequality

The second graph (B) shows $x \geq 16$ and this matches the 3rd inequality

The third graph (C) shows $x > 9$ and this matches the 1st inequality

Hence, the correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

Learn more here: brainly.com/question/17448505

8 0

2 years ago

Is the mean or median a better measure for a typical amount of water water produced in the experiment? Explain

azamat

Answer:

mean

Step-by-step explanation:

because its all of the amounts of water added together and divided by the number of different amounts

3 0

3 years ago

A larger number is double the sum of 3 and a smaller number. The larger number is 2 less than 3 times the smaller number. If y r

Ratling [72]

Y > x
y = 2(3+x)
y = 3x-2
------------------------------
2(3+x) = 3x-2
2(3+x) - (3x-2) = 0
6 + 2x -3x + 2 = 0
8 -x = 0
x = 8
---------------------------
y = 2(3+x) = 2(3+8) = 22
y = 3x-2 = 3*8 -2 = 22
----------------------------------
x = 8 ; y = 22

7 0

3 years ago

Read 2 more answers

If f(x) = 3x5 + 4x3 + 3, then what is the remainder when f(x) is divided by x - 3?