What is the solution to this inequality?
1 answer:
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Answer:
1. The sides are: 38.5, 39.5, 40.5 and 41.5
2. Presently, Inzo is 15 years old and Miz is 10 years old
3.
4. Possible pairs are: (12, 14), (16, 18) and (20, 24)
5.
Step-by-step explanation:
The question has lots of missing details. See the comment section for complete question
Solving (a):
Given
Shape: Quadrilateral
Sides: Consecutive
Let one of the sides be x. The other sides will be x + 1, x + 2 and x + 3.
So, the perimeter is:
This gives:
Collect Like Terms
Divide both sides by 4
<em>So, the sides are: 38.5, 39.5, 40.5 and 41.5</em>
<em></em>
Solving (b):
Given
Presently:
Five years ago: --- (Missing from the question)
Required: Determine their present ages
Substitute for Inzo in the second equation
Multiply both sides by 3
Collect Like Terms
Divide both sides by 2
Substitute 10 for Miz in
<em>So presently, Inzo is 15 years old and Miz is 10 years old</em>
Solving (3):
Given
Express Train:
Local Train:
Required: Determine the distance between A and B
Distance is calculated as:
For the express train:
For the local train
Distance between both stations are equal; So,
Collect Like Terms
Divide by 55
Substitute 36.82 for t in
Solving (4):
Let the even numbers be: n and n + 2.
Sum greater than 24:
Sum less than 60:
So, we have:
Collect Like Terms
Collect Like Terms
Divide by 2
So, we have:
and
So, possible pairs are: (12, 14), (16, 18) and (20, 24)
Solving (5):
Given
Required: Find the possible lengths
Let the length be L.
Perimeter is calculated as:
So, we have:
Divide through by 4
Hence, length is less than 38m (e.g. 37m)
Answer:
Step-by-step explanation:
The missing image is attached below.
From the given information
The number of players is 44.
From the box plot;
The minimum weight = 154 pounds
The first quartile Q₁ = 159 which is 25% of the data below 159 pounds.
The second quartile Q₂ = 213 which is 50% of the data below 213 pounds
The third quartile Q₃ = 253 which is 75% of the data below 253 pounds
The maximum weight = 268 pounds.
Here, the value of 213 is the middle value and which signifies the median.
The 50% of the data are located both on the left side and the right side of the median.
Thus, the percentage of players weighting greater than or equal to 213 pounds is 50%.
